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vovangra [49]
3 years ago
7

1,Justin rides his bicycle 2.5 kilometers to school. Luke walks 1,950 meters to school.How much farther does Justin ride to scho

ol than Luke walks to school?Explain
A.550 meters
B.55 meters
C.55 kilometers
D. 550 kilometers

2.The length of a room is 10 1/2 feet.What is the length of the room in inches? Explain

A.132 inches
B. 126 inches
C. 121 inches
D. 22 1/2 inches
Mathematics
1 answer:
kirill [66]3 years ago
6 0
1. A. 550 meters.
this is because 2.5 km = 2500 meters, since there are 1000 meters in one kilometer.
therefore, 2500 - 1950 = 550 meters.
2. B. 126 inches.
this is because there are 12 inches in one foot, so we multiply 12 by 10 since there are 10 full feet. this leaves us with 120. then, we add half a foot, which is 6 inches. therefore, it is 126 :)
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Answer:

The length of the shorter base of the little trapezoid trail is 1 mi.

Step-by-step explanation:

Let the shorter base of the large trapezoid is S and the larger base of the large trapezoid is L.

Similarly, assume that the shorter base of the small trapezoid is s and the larger base of the small trapezoid is l.

Since, the trapezoids are similar, so

\frac{L}{l} = \frac{S}{s}

Now, given that S = 2 mi, L = 8 mi and l = 4 mi and we have to find s.

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3 years ago
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Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

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c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

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