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stepan [7]
1 year ago
10

Which data set is the most spread from its mean?

Mathematics
1 answer:
spin [16.1K]1 year ago
7 0

Option B (22,16,18,36)

Mean- Mean is an average of the data collected in the data set. It can be found by dividing the sum of the values by the number of values. Median is the middle value of the data set when the values are placed in order from least to greatest.

It is easy to calculate: add up all the numbers, then divide by how many numbers there are.

Add all the numbers (22+16+18+36) = 92

Avarage = sum of the all given numbers/ total numbers

total numbers =4

so avarage= mean= 92/4 =23

(22,16,18,36) has the most spread because one number as low as 16 and one as high as 36. Our mean is 23, so that means that the spread is huge.

Hence the answer is (22,16,18,36).

For more information about Mean

visit : brainly.com/question/1635504

#SPJ9

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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

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In an orchard, there are 16 apple trees, 22 orange trees, and a cherry tree. What is the ratio of apple trees to orange trees? O
AlladinOne [14]

Answer:

C.  16 : 22

Step-by-step explanation:

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