Dr. Hoover allot his time on Tuesday for an annual checkup is 147 minutes and for a sick visit is 42 minutes (Total 189 minutes)
On Wednesday appointment, he allot his time for an annual checkup is 147 minutes and for a sick visit is 21 minutes (Total 168 minutes)
solution
Let us assume, minutes for annual checkup denoted as x and
minutes for sick visit denoted as y
The equation of Tuesday visit is 
The equation of Wednesday visit is 
by changing the signs of the equation 2 and subtract it from the equation 1 we will get 1y = 21 minutes
to substitute y =1 in the equation 2 we get





then now we have substitute both x = 49 and y= 21 in equation ----- 2
we will prove that

so the Tuesday appointment , the time allotted for an annual checkup is 147 minutes and for a sick visit is 42 minutes (Total 189 minutes)
On Wednesday appointment, the time allotted for an annual checkup is 147 minutes and for a sick visit is 21 minutes (Total 168 minutes)
Answer:
<h3>.8^6/8</h3><h3>( 262,144)/8</h3><h3><u>=</u><u> </u><u>3</u><u>2</u><u>,</u><u>7</u><u>6</u><u>8</u></h3>
Step-by-step explanation:
<h2>Hope that will help you</h2>
Answer:
352 cm/s
Step-by-step explanation:
circ = 44pi
speed = distance * time
distance = circ * 4 = 176pi
speed = 176pi/0.5
Formula is y = a(x-h)^2 + k
Where h is 1 and k is 1
f (x) = a(x-1)^2 + 1
-3 = a(0-1)^2 + 1
-3 = a(-1)^2 + 1
-3 = a(1) + 1
-3 - 1 = a
-4 = a
a = -4
A must be equal to -4
y = -4(x-1)^2 + 1
0 = -4(x-1)^2 + 1
4(x^2 - 2x + 1) - 1 = 0
4x^2 - 8x + 4 - 1 = 0
4x^2 - 8x + 3 = 0
4x^2 - 8x = -3
Divide fpr 4 each term of the equation....x^2 - 2x = -3/4
We must factor the perfect square ax^2 + bx + c which we don't have. We must follow the rule (b/2)^2 where b is -2....(-2/2)^2 =
(-1)^2 = 1 and we add up that to both sides
x^2 - 2x + 1 = -3/4 + 1
x^2 - 2x + 1 = 1/4
(x-1)^2 = 1/4
square root both sides x-1 = (+/-) 1/2
x1 = +1/2 + 1 = 3/2
x2 = -1/2 + 1 = 1/2
x-intercepts are 1/2 and 3/2, in form (3/2,0); (1/2,0)