Answer:
Step-by-step explanation:
The square root is possible only if y≤0
if y>0 the expression lose meaning, in fact (-)(+)(+) = (-) and a square root of a negative number doesn’t exist. x^2 is a square so it is ever positive if x is not 0
if y≤0 can be rewritten as:
3(-27x^2y^7)^1/2
or if we want simplify the expression:
^1/2
we have to put the symbol of absolute value between x and y because a x^2 and y^6 are numbers that are ever positive, while x and y^3 can be also negative. Thanks to the simbol of absolute value we can “force” them to be positive
1\ x-5=2 7
2\ 6+x=9 3
3\ 10=4+x 6
4\ 1/2(x-2)=3 2
5\ 3x=5+x 2 1/2
6\ 2x+4=6 1
7\ 8=2x-5 6 1/2
8\ x+3/2=7 5 1/2
9\ x+4=10 6
10\ 9=5x-3x 4 1/2
11\ 12=3x-4 5 1/3
12\ 2(x+1)=12 5
13\ 2x-3/2x=2 1
Answer: x only can have complex values, not real values.
x = -1/4 - 1/4i and x = -1/4 + 1/4 i
Explanation:
Finding the possible values of x in the expression given is solving the quadratic equation.
8x² + 4x = - 1
Rearrange the terms:
8 (x² + x/2) = - 1 ← common factor 8 in the left side
x² + x/2 = - 1/8 ← division property
x² + x/2 + 1/16 = - 1/8 + 1/16 ← addition property
(x + 1/4)² = -1/8 + 1/16 ← -factor the perfect square trinomial in the left side
(x + 1/4)² = - 1/16 ← add the fractions in the right side
x + 1/4 = (+/-) √ (-1/16) ← square roots on both sides
x + 1/4 = (+/-) (1/4)i ← complex solution
x = - 1/4 +/- 1/4i
x = - 1/4 - 1/4i and x = - 1/4 + 1/4 i ← answer
Answer:
BC
Step-by-step explanation:
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