Given the directrix of y = 6 and focus of (0, 4), which is the equation of the parabola?\
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So the total amount of money is: (65 x +50 ) cents
Answer: It rounds to <u>28 km</u>
Explanation:
The units or ones digit is "7". The next digit over (9) is five or larger. This means we bump the 27 up to 28. Everything after the 7 is ignored.
So we could have something like 27.999871212512 and we still follow the same idea of focusing on the 27, bumping it up to 28, and everything else gets ignored.
The reason for this is because 27.9 is much closer to 28 than it is to 27. Draw out a number line to help see this. Split the region from 27 to 28 into 10 equal pieces. The 9th little piece represents 27 & 9/10 aka 27.9
Refer to the number line diagram below.
The perimeter would be 
and the area would be 
.
The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;
Which gives;
6•x² - 106•x + 315 = 0
Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- Height = x ≈ 4.55 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
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