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rosijanka [135]
2 years ago
6

How do researchers prepare an intron-free copy of a eukaryotic gene for use in creating transgenic bacteria?

Biology
1 answer:
Tcecarenko [31]2 years ago
3 0

The researchers prepare an intron-free copy of the eukaryotic gene for the use in creating the transgenic bacteria by using the reverse transcriptase to make the cDNA from the mature mRNA

The structure of the eukaryotic genes. Most of the eukaryotic genes are contain the segments of the coding sequences (exons) that interrupted by the noncoding sequences (introns). Both the exons and the introns are transcribed to yield a long and primary RNA transcript.

Eukaryotic DNA is the linear, compacted into the chromosomes by the histones, and has the telomeres at each end to protect from the deterioration. The Prokaryotes contain the circular DNA in addition to the smaller, transferable DNA plasmids. Eukaryotic cells contain the mitochondrial DNA in the addition to the nuclear DNA

To know more about eukaryotic gene visit:

brainly.com/question/28297163

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Type a paragraph about DNA describing the following:
earnstyle [38]

Answer:

1. DNA molecule is a double helix of 2 complementary polynucleotide strands;;

2. The two strands coil around each other to form a right-handed double helix;;

3. The strands are antiparallel, i.e. run in opposite directions (one strand runs in

the 5’ to 3’ direction while the complementary strand runs in the 3’ to 5’

direction);;

4. Each (polynucleotide) strand consists of very long chain of nucleotides, with

each nucleotide comprising of a deoxyribose sugar, a phosphate group and one

of the four nitrogenous bases - Adenine, Thymine, Cytosine or Guanine;;

5. Each strand contains a sugar-phosphate backbone – comprising of nucleotides

arranged in sequence, held together by phosphodiester bonds between C3 of

the (deoxyribose) sugar of one nucleotide and C5 of the (deoxyribose) sugar of

the adjacent nucleotide;;

6. The nitrogenous bases are arranged as side groups of the polynucleotide

strands (oriented toward the central axis);;

7. The width between the 2 sugar-phosphate backbones is constant at 2nm, this is

equal to the width of 1 base pair, i.e. 1 purine + 1 pyrimidine;;

8. One complete turn of the double helix measures 3.4nm in length and comprises

10 base pairs;;

9. The double helical nature of DNA results in the surface of the DNA molecule to

have major grooves and minor grooves;;

10. The nitrogenous bases of 1 strand pair with nitrogenous bases of the opposite

strand via hydrogen bonds. There are 2 hydrogen bonds between adenine and

thymine, and 3 hydrogen bonds between cytosine and guanine;;

11. Base pairing is complementary, i.e. adenine pairs with thymine, guanine pairs with cytosine. The base-pairing is specific and the 2 strands are said to be

complementary (i.e. no. of A = no. of T, no. of G = no. of C,);;

12. (extra pt) The DNA molecule is further stabilised by hydrophobic interactions between the stacked nitrogenous bases;;

13. The nucleosomes are connected by linker DNA and associates with H1 forming the nucleohistone complex;

14. Interactions between the H1 histones (histone tails of octamers and linker DNA) results in further coiling into a 30nm chromatin fibre;

15. The 30nm chromatin fibre form looped domains that are attached to a scaffold of non-histone proteins, giving rise to a 300nm fibre;

6 0
3 years ago
What are the benefits of regeneration to the life of a tropical forest​
ololo11 [35]

Answer:

For tropical forest restoration to result in long-term biodiversity gains, native trees must establish self-sustaining populations in degraded sites. While many have asked how seedling recruitment varies between restoration treatments, the long-term fate of these recruits remains unknown. We address this research gap by tracking natural recruits of 27 species during the first 7 years of a tropical forest restoration experiment that included both planted and naturally regenerating plots. We used an individual-based model to estimate the probability that a seedling achieves reproductive maturity after several years of growth and survival. We found an advantage for recruits in naturally regenerating plots, with up to 40% increased probability of reproduction in this treatment, relative to planted plots. The demographic advantage of natural regeneration was highest for mid-successional species, with relatively minor differences between treatments for early-successional species. Our research demonstrates the consequences of restoration decision making across the life cycle of tropical tree species.

Explanation:

4 0
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What are three environmental factors that effect photosynthesis
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Air water and carbon dioxide 
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3 years ago
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4 years ago
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PLEASE HELP! ASAP! FIFTEEN POINTS!
oee [108]

Answer:

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An example of shared anatomy is sharks and dolphins. types of analogous structures, such as dolphins and sharks, do not prove species are related, but rather they support the Theory of Evolution by show how species do build up adaptations in order to fit into their environments

Molecular biology because DNA and the genetic code reflect the shared ancestry of life. DNA comparisons can show how related species are.

in recent research is has been shown that the myoglobin and hemoglobin sequences for dozens of mammals, birds, reptiles, amphibians, fish, worms, and molluscs were related.

Structural similarities is when different animals share the same structural similarities. For example the skeletons of turtles, horses, humans, birds, and bats are very similar, despite their t different ways of life and the diversity of their environments.  

Explanation:

6 0
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