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natta225 [31]
3 years ago
13

Jackson builders is constructing new homes in the Parkway subdivision.The company needs the logic for an application that ncalls

a method that computes the final price for construction of a new home.The main() method prompts the user for the number of bedrooms and bathrooms in the home and for the salespersons commission expressed as a percentage,and then displays the final price.Create calculatePrice() method that determines the final price and returns the value to the calling method.The calculatePrice() method requires three arguments:bedrooms,baths,and salesperson commission rate.A homes final price is the sum of the base price of $100,000 plus $20,000 per bedroom,$30,000 per bathroom,and the salesperson commission amount. in programming logic and design fourth edition Joyce Farell pg,246 no 7 need logic for application
Computers and Technology
1 answer:
lord [1]3 years ago
8 0
<span>The calculatePrice() method can be written in C. It will use and return doubles (which allows for decimals). It will calculate the house price of $100K + $20K per bedroom and $30K per bathroom. Next it will take that price and append the sales percentage and return that value.
double calculatePrice(decimal numBedrooms, decimal numBathrooms, decimal salesPercentage)
{
decimal housePrice = 100000 + (20000 * numBedrooms) + (30000 * numBathrooms);
return housePrice + (housePrice * salesPercentage);
}</span>
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Answer:

#include <iostream>

using namespace std;

int * reverse(int a[],int n)//function to reverse the array.

{

   int i;

   for(i=0;i<n/2;i++)

   {

       int temp=a[i];

       a[i]=a[n-i-1];

       a[n-i-1]=temp;

   }

   return a;//return pointer to the array.

}

int main() {

   int array[50],* arr,N;//declaring three variables.

   cin>>N;//taking input of size..

   if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..

   return 0;

   for(int i=0;i<N;i++)

   {

       cin>>array[i];//prompting array elements..

   }

   arr=reverse(array,N);//function call.

   for(int i=0;i<N;i++)

   cout<<arr[i]<<endl;//printing reversed array..

   cout<<endl;

return 0;

}

Output:-

5

4 5 6 7 8

8

7

6

5

4

Explanation:

I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.

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