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MA_775_DIABLO [31]
3 years ago
13

A brick has a weight of 23N. The brick is flat and smooth on the side in contact with the floor having measurements ( height= 5c

m, length =20cm, width=10cm).
A)Calculate the area of the brick in contact with the floor. Give your answer in cm2.
B)Calculate the pressure of the brick on the floor.​
Computers and Technology
1 answer:
devlian [24]3 years ago
8 0

Answer:

A)Area = 200cm^{2}

B) Pressure = 0.115 N/cm^{2}

Explanation:

Assuming that the brick is flat on the floor with its largest face towards the floor and not on its side, then we can calculate the area of that face by multiplying the length by the width like so...

Area = length * width

Area = 20cm * 10cm

Area = 200cm^{2}

The formula for calculating pressure is force divided by area. Therefore, since we just finished calculating the area and the force is given to us in the question (23N) we can simply plug in these values and solve for the pressure.

Pressure = Force / Area

Pressure = 23N / 200cm^{2}

Pressure = 0.115 N/cm^{2}

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Answer:

Non-broadcast media incorporates

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Explanation:

Non-broadcast media is a phrase used to represent audio and visual communications that can be obtained at any moment. Non-broadcast media is the knowledge that can be switched on and off, suspended, rewound, and fast-forwarded at certain times.

Examples of non-broadcast productions

Non-broadcast media incorporates

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4 0
3 years ago
What is the purpose of application software policies?
timofeeve [1]

Answer:

d. They serve to help educate users on how to use software more securely.

Explanation:

A software policy can be defined as a set of formally written statements that defines how a software application or program is to be used.

The purpose of application software policies is that they serve to help educate users on how to use software more securely. It must be easy to read, learn and understand by the end users.

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3 years ago
Assume the system with 256B memory and 64B cache and the block size of 16 bytes. I.e., there are 4 blocks in the cache.
Arada [10]

Answer:

a. 100%

b. 50%

c. 66.6%

Explanation:

a.

The memory references D6, 58, D8, 9A, DE and 5C all results in misses and the miss ratio is 100 (that is , 6 misses/ 6 references*100 = 100%)

b.

If fully associative cache is used, there will be a 3 cache misses with miss ratio of (3/6*100) = 50%.

c.

With a 2-way set-associative cache, 4 memory reference misses will occur, with a miss ratio of (4/6*100)= 66.6% misses.

6 0
3 years ago
Write the proghrams for the following:
belka [17]

Answer:

a)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c;

   cin>>a>>b;

   if(a^b)//X-OR operator in C++.

   c=true;

   else

   c=false;

   cout<<c;

return 0;

}

b)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c,d;

   cin>>a>>b>>c;

   if((a^b)^c)//X-OR operator in C++.

   d=true;

   else

   d=false;

   cout<<d;

return 0;

}

Explanation:

The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.

In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.

5 0
3 years ago
Imagine the user types in a complete sentence, but we want to read only the first word and place it in the String variable word.
Vladimir [108]

Answer:

import java.util.Scanner;

public class FirstWord {

   public static void main(String[] args) {

       //NOW YOU WANT TO COLLECT INPUTS FROM THE STUDENT OR USER

       //IMPORT THE SCANNER CLASS FIRST  outside your class

       // THEN YOU CREATE AN OBJECT OF THE SCANNER CLASS

       Scanner input = new Scanner(System.in);

       

       //CREATE A VARIABLE TO HOLD THE USER INPUT

       String text = input.nextLine();

       

       //The variable holder will be used to store characters from the for loop

       String holder="";

       

       //Create a for loop that loops through the user's input

       for(int i=0; i<text.length(); i++){

           //As the loop increases, we get the character in the user's input and store them one by one in the variable holder

           holder+=text.charAt(i);

           if(text.charAt(i)==' '){

               //If the loop encounters a space, it means a complete word has been gotten from the user's input

               //Then the break below Breaks the loop, and the loop stops running

               break;

           }

       }

       System.out.println(holder);

}

Explanation:

text.length() returns the length of the sequence of characters present in length

text.charAt(a number) Returns the char value at the specified index. An index ranges from 0 to length() - 1. The first char value of the sequence is at index 0, the next at index 1, and so on, as for array indexing.

Create a for loop

How does a for loop work?

It collects a starting point, an end point and an increment respectively....all these are passed in as arguments into the for loop

For example, the code above starts from 0, calculates the number of characters in the user's input and sets it as the end point, the loop runs from zero to the length of the text of the user...

Note: i++ in the loop is the increment, it means the loop increases by 1

8 0
3 years ago
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