Question

A brick has a weight of 23N. The brick is flat and smooth on the side in contact with the floor having measurements ( height= 5cm, length =20cm, width=10cm).
A)Calculate the area of the brick in contact with the floor. Give your answer in cm2.
B)Calculate the pressure of the brick on the floor.​

Answer 1

Answer:

A)Area = 200$cm^{2}$

B) Pressure = 0.115 N/$cm^{2}$

Explanation:

Assuming that the brick is flat on the floor with its largest face towards the floor and not on its side, then we can calculate the area of that face by multiplying the length by the width like so...

Area = length * width

Area = 20cm * 10cm

Area = 200$cm^{2}$

The formula for calculating pressure is force divided by area. Therefore, since we just finished calculating the area and the force is given to us in the question (23N) we can simply plug in these values and solve for the pressure.

Pressure = Force / Area

Pressure = 23N / 200$cm^{2}$

Pressure = 0.115 N/$cm^{2}$