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Akimi4 [234]
3 years ago
10

The two types of one-time-password tokens are ______ and ______.

Computers and Technology
2 answers:
Nutka1998 [239]3 years ago
5 0

Answer:

event based and time based

Explanation:

OTP tokens come in two types: event-based (HOTP) and time-based (TOTP). Event-based OTP tokens generate new codes at the press of the button and the code is valid until it is used by the application. Time-based OTP tokens generate codes that are valid only for a certain amount of time (eg, 30 or 60 seconds), after which a new code must be generated

kakasveta [241]3 years ago
3 0

Answer:

COUNTER AND TIME BASED

Explanation:

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PtichkaEL [24]
Computer language is essential
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3 years ago
Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

3 0
3 years ago
Write a recursive function that calculates if two binary trees are similar?
ahrayia [7]

Answer:

bool identicaltrees(Node* root1,Node* root2)//function of type boolean true if idenctical false if not.

{

   if(root1==NULL&&root2==NULL)//both trees are null means identical.

   return true;

   if(roo1 && root2)

   {

       if(root1->data==root2->data)//condition for recursive call..

       {

           return (identicaltrees(root1->left,root2->right)&&identicaltrees(root1->right&&root2->right);

       }

   }

   else

   return false;

}

Explanation:

In this function it of type boolean returns true if both the trees are identical return false if not.First we are checking root node of both the trees if both are null then they are identical returning true.

If both root nodes are not null then checking their data.If data is same then recursively traversing on both trees and checking both trees.

else returning false.

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Answer:

The name of the components of the given labelled circuit is:

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A bubble like object in the circuit is a bulb which lights up when current moves through the circuit.

A component connected to the negative terminal of batter source is a switch.

Then open circuit is an open as the key of the switch is open.

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