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Kobotan [32]
2 years ago
14

You measure 10 trials of the time it takes a snail to travel 2 cm. you find the average and the standard deviation of these tria

ls. what are the units on the standard deviation?
Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
8 0

For "You measure 10 trials of the time it takes a snail to travel 2 cm. " The  Unit of standard deviation will be cm

This is further explained below.

<h3>What are the units on the standard deviation?</h3>

Generally, The standard deviation is a measurement that is used in statistics to determine the degree of variation or dispersion that exists within a given collection of data.

A standard deviation that is low suggests that the values in the set have a tendency to be near to the mean of the set, while a standard deviation that is large shows that the values are spread out across a range that is more extensive.

In conclusion, You conduct ten separate measurements of the amount of time it takes a snail to go a distance of two centimeters. The centimeter will serve as the unit of standard deviation.

Read more about standard deviation.

brainly.com/question/16555520

#SPJ4

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a car traveling at a constant speed travels 175 miles in 4 hours? How many minutes will it take for the car to travel 1000 feet?
liubo4ka [24]

Answer:

0.26 minutes

Step-by-step explanation:

So if you want to solve this, you need to make all the units the same first. What you first need to work on is the rate, since what it is asking is minutes given distance in feet.

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We then convert the rate knowing this:

\dfrac{174\:miles}{4\:hours}\times\dfrac{5280ft}{1\:mile}\times\dfrac{1hour}{60\:minutes} = \dfrac{918,720ft}{240\:minutes} = \dfrac{3828\:feet}{1 minute}

In short, the car is traveling 3,828 ft every minute.

To determine how many minutes it will take for the car to travel just remember that:

speed=\dfrac{distance\:travelled}{time}\;\rightarrow\;time=\dfrac{distance\;travelled}{speed}

Now we plug in what we know and solve what we don't know:

time=\dfrac{1000feet}{\dfrac{3828ft}{1minute}}\;\rightarrow\;1000ft\times\dfrac{1\:minute}{3828ft}=0.26\:minutes

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