I need help with 1 and 3 the slope is 3/4

Mathematics

2 answers:

PSYCHO15rus [73]2 years ago

8 0

Answer:

Step-by-step explanation:

11Alexandr11 [23.1K]2 years ago

8 0

Answer:

y intercept is 4

the equation is y= 3/4 + 4

Slope intercept equation y=mx+b

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Help me with this question plzzzz

zubka84 [21]

V = L * W * H
V = 1/4 * 2/3 * 3/5
V = (1 * 2 * 3) / (4 * 3 * 5)
V = 6/60 reduces to 1/10 m^3 <==

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3 years ago

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Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

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3 years ago

Manny used 8 tenth-size parts to model 8/10. Ana used fewer parts to model an equivalent fraction. How does the size of a part i

viktelen [127]

Alrighty, let's think of it like this: You are trying to fill a box with a bunch of sports balls. You have tiny little golf balls, and you have giant bowling balls. You need to fill this same box all the way up.

If you fill it with the tiny golf balls, you are going to need a whole lot of them!

If you are putting in bowling balls, only a few of them will fit, because they are so much bigger.

When it comes to your fraction, the box is the the number 8/10. That number will not change because we are not changing the size of the box.

We are just changing what we are filling it with. Manny, can fit 8 parts, or in this case balls, into the box.

It says Ana uses fewer parts, so she cannot fit as many in as Manny.

This means that Manny would have the golf balls, since he can fit more in than Ana, who must have the bowling balls.

So which is bigger? A bowling ball or a golf ball?

A bowling ball, which is what Ana has. So Ana's part will be bigger in size.

4 0

2 years ago

Read 2 more answers

Please show me how to solve the initial value problem y'=tanx y(pi/4)=3

AlexFokin [52]

The ODE is separable, i.e. you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx$

Integrating both sides gives the general solution.

$\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx$
$y=-\ln|\cos x|+C$

Given that $y\left(\dfrac\pi4\right)=3$ , we have

$3=-\ln\left|\cos\dfrac\pi4\right|+C$
$3=-\ln\dfrac1{\sqrt2}+C$
$3-\ln\sqrt2=C$

and so the particular solution to the IVP is

$y=-\ln|\cos x|+3-\ln\sqrt2$
$y=3-\ln|\sqrt2\cos x|$