y = a(x - b)^2 + c has vertex (b , c)
so here the vertex is (1, -36)
3/162=3/60+3/120 3/162 is equal to 2/152
4x - 1 < 7
To solve for x:
4x - 1 + 1 < 7 + 1
4x < 8
Divide both sides by 4:
4x/4 < 8/4
x < 2
Answer:
At ; I = 3, P is at maximum
Step-by-step explanation:
P ( I ) = ![[ \frac{80 I}{I^2 + I + g } ]](https://tex.z-dn.net/?f=%5B%20%5Cfrac%7B80%20I%7D%7BI%5E2%20%2B%20I%20%2B%20g%20%7D%20%5D)
at I = 3
P" ( I ) < 0
therefore at I = 3 the value of P( I ) is at maximum
attached below is the detailed solution
Answer:
b
Step-by-step explanation: