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Oksana_A [137]
1 year ago
8

a tank is 4/5 full water . after drawing of 190 litres of water it is just 1/6 full . what is the capacity​

Mathematics
1 answer:
xxTIMURxx [149]1 year ago
3 0

Answer:

The capacity of water in the tank is 300 litres

Step-by-step explanation:

Let the unknown capacity be x

4/5 of x-190 litres = 1/6 of x

4x/5-190 litres = x/6

Cross x/6 and 190 litres over the equation sign

4x/5-x/6 = 190 litres

The LCM is 30

(24x-5x)/30 = 190 litres

19x/30 = 190 litres

Cross multiply

190 litres*30 = 19x

5700 litres= 19x

Divide through by 19

x = 300 litres

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The current population of a small town is 10,500, and its population is expected to grow at a rate of 5% per year. Which of the
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3 years ago
Patrick pizza parlor is famous for its giant circular pizza, which has an area of 1519.76 square inches. Approximately what is t
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Answer:

Step-by-step explanation:

Patrick pizza parlor is famous for its giant circular pizza, which has an area of 1519.76 square inches. The pizza is circular in shape. The formula for determining the area of a circle is expressed as

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Therefore,

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7 0
3 years ago
Use the given zero to find the remaining zeros of each function f(x)=2x^4+5x^3+5x^2+20x-12 zero:-2i
frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

  1. The Fundamental Theorem of Algebra tells us that any polynomial has <em>as many zeroes as its degree</em>. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
  2. Complex zeroes come in pairs. Specifically, they come in <em>conjugate pairs</em>. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both x-2i and x+2i are factors of f(x), and furthermore, their product, x^2+4, is <em>also</em> a factor. To see what's left after we factor out that product, we can use polynomial long division to find that

2x^4+5x^3+5x^2+20x-12=(x^2+4)(2x^2+5x-3)

I'll go through to steps to factor that second expression below:

2x^2+5x-3=2x^2+6x-x-3\\=2x(x+3)-(x+3)\\=(2x-1)(x+3)

Solving both of the expressions when f(x) = 0 gets us our final two zeroes:

2x-1=0\\2x=1\\x=1/2

x+3=0\\x=-3

So, the remaining zeroes are 1/2 and 3.

8 0
3 years ago
Read 2 more answers
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