Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.
So we can use formula of perimeter of rectangel to find it's possible dimensions.
We knwo that perimeter of the rectangle is given by 2(L+W)
where L is lenght and W is width.
Given perimeter is 20 so we get:
2(L+W)=20
L+W=10
L=10-W
So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.
Let W=4
Then L=10-W=10-4=6
Hence we just have to draw a rectangle having length 6 and width 4.
So the final answer will be picture in the attached graph.
Answer:
Solution: Option C
Step-by-step explanation:
Our goal here is to factor the expression such that it is converted into the circle equation (x - a)² + (y - b)² = r² where r = radius centered at point (a,b).
(Factor the expression "x² + 8x")
(Factor the expression "y² - 12y")
That leaves us with the expression
, or in other words
. As you can see our solution is option c.
Answer:
=
+ 6
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
- 11 - (- 17) = - 5 - (- 11) = 1 - (- 5) = 6
A recursive rule allows a term to be found by adding d to the previous term, thus
=
+ 6 with a₁ = - 17
Answer:
0.38 and 0.7 maybe it's the answer
Step-by-step explanation:
power of 10 in above questions are 2 and 3 respectively