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mel-nik [20]
3 years ago
14

Draw a polygon with the given conditions in a coordinate plane of rectangle with a perimeter of 20 units

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.

So we can use formula of perimeter of rectangel to find it's possible dimensions.

We knwo that perimeter of the rectangle is given by 2(L+W)

where L is lenght and W is width.

Given perimeter is 20 so we get:

2(L+W)=20

L+W=10

L=10-W


So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.

Let W=4

Then L=10-W=10-4=6

Hence we just have to draw a rectangle having length 6 and width 4.

So the final answer will be picture in the attached graph.

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Calculate the measure of the major arc MPN.
34kurt

Answer:

  310°

Step-by-step explanation:

The sum of arcs around a circle is 360°.

  MPN +MN = 360°

  MPN = 360° -MN . . . . . . . . subtract MN

  MPN = 360° -50° = 310° . . . fill in the given value

The measure of major arc MPN is 310°.

4 0
2 years ago
Answer the question with explanation;​
PSYCHO15rus [73]

Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0

Therefore, by the series divergence test, the series \sum_{n=1}^\infty\frac{n^2}{(n+1)^2} diverges.

EDIT: To VectorFundament120, if (x_n)_{n\in\mathbb N} is a sequence, both \lim x_n and \lim_{n\to\infty}x_n are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.

7 0
2 years ago
Read 2 more answers
Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due
ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

        Formula :   d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

      Formula : D=\sqrt{(x2-x1)^2+(y2-y1)^2}

⇒                     D = \sqrt{20^2t^2+15(t-1)^2}

Now let           F(t) = D^2(t)

                ∵    F'(t) = 800t + 450(t-1) =  1250t -450\\F'(t) =0

⇒                     t= 450/1250

⇒                     t= .36 hours

⇒                       = 21 min 36 sec

Since F"(t)=0,

∴ This time gives us a minimum.

Thus, The two boats will closet together at 2:21:36 pm.

3 0
3 years ago
Find two solutions of y=2x-3<br> Point 1: (x,y) ---&gt;<br> Point 2: (x,y) ---&gt;
Ksenya-84 [330]

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Somebody please help me with this question
denis23 [38]

Answer:

c is the correct answer

Step-by-step explanation:

3 0
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