3 packets of French fries, 2 cheeseburgers, and one drink cost $10.95. 1 packet of French fries, 2 cheeseburgers, and 3 drinks c
1 answer:
Answer:
The price of 1 packet of French fries, 1 cheeseburger, and one drink cost $5.55
Step-by-step explanation:
Let
x ----> the price of 1 packet of French fries
y ---> the price of 1 cheeseburger
z ---> the price of one drink
we know that
----> equation A
---> equation B
Adds equation A and equation B
Divide both sides of the equation by 4
----> equation C
The equation C means ----> The price of 1 packet of French fries, 1 cheeseburger, and one drink cost $5.55
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Answer:
a)
Operating room x 1 2 3 4
P(x) 0.15 0.25 0.4 0.2
b)
The graph of probability distribution is in attached image.
c)
All the probabilities lies in the range (0 to 1) and the probabilities add up to 1 so, the computed probability distribution is the valid probability distribution.
Step-by-step explanation:
Number of operating rooms Days
1 3
2 5
3 8
4 4
a)
Sum of frequencies=1+2+3+4=10
Operating rooms x frequency f Relative frequency
1 3 3/20=0.15
2 5 5/20=0.25
3 8 8/20=0.4
4 4 4/20=0.2
So, using the relative frequency approach, a discrete probability distribution for number of operating rooms in use on any given day is
Operating room x 1 2 3 4
P(x) 0.15 0.25 0.4 0.2
b)
The graph of probability distribution is in attached image.
c)
There are two conditions for a probability distribution to be valid
1. All probability must ranges from 0 to 1.
2. All probabilities must add up to 1.
We can see that all the probabilities lies in the range (0 to 1), so, condition 1 is satisfied.
For condition 2,
sum[p(x)]= 0.15+0.25+0.4+0.2=0.4+0.6=1.
As the probabilities add up to 1, so the condition 2 is also satisfied.
Thus, the computed probability distribution is the valid probability distribution.
