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Lady bird [3.3K]
1 year ago
13

Please answer as fast as possible

Mathematics
1 answer:
umka21 [38]1 year ago
5 0

According to the square root of the given terms, The options A And C is correct which is:

Square root of one hundred thirty > one hundred eleven

One hundred eleven > square root of one hundred thirty.

According to the statement

we have to compare the square root of the 130 and 111 with the given options.

So, For this purpose, we know that the

Square root is a factor of a number that, when multiplied by itself, gives the original number.

So, From the given information:

The numbers are 130 and the 111.

Then

Square root of 130 = 11.40

And

Square root of 111 = 10.53.

Now compare it with the given options:

A.

square root of one hundred thirty > one hundred eleven

11.40 > 10.53

This is correct option.

B.

square root of one hundred thirty = one hundred eleven

11.40 = 111

This is wrong option.

C.

one hundred eleven > square root of one hundred thirty

111 > 11.40

This is a correct option.

D.

one hundred eleven < square root of one hundred thirty

111 < 11.40

This is a wrong option.

So, According to the square root of the given terms, The options A And C is correct which is:

Square root of one hundred thirty > one hundred eleven

One hundred eleven > square root of one hundred thirty.

Learn more about square root here

brainly.com/question/428672

#SPJ1

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230 is equal to _____.
Makovka662 [10]

200+30 but its hard to understand what you are trying to say so please be more specific

3 0
4 years ago
Read 2 more answers
I need help plss!! I don’t understand
MA_775_DIABLO [31]

Since it says what the area of the circle is, you need to work the problem backwards from finding the area. So it would be 100 ÷ 3.14 = 31.84 that is the radius. Next you need to find the diameter, so 31.84 × 2 = 63.68. Now you multiply 63.68 × 3.14 = 199.95, round that to 200, divide 200 ÷ 2 = 100 ÷ 2 = 50 miles

Answer= 50 miles

4 0
3 years ago
Which operation should you perform first when you simplify 63-(2+54x6) / 5
koban [17]

Answer:

Multiply 54 and 6

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Identify the best big-O estimate for the number of comparisons used by the algorithm that determines the number of 1s in a bit s
Westkost [7]

Answer:

0(n)

Step-by-step explanation:

Result previous exercise:  

procedure count(a1a2...an : string with n > 1)

i:=0

for k:=1 to n

if ak =1 then i:=i + I

return i  

<em>Note</em><em>: If you use a different algorithm, then you could possible get different results.  </em>

<u>SOLUTION  </u>

There is only one part of the code that contains an operation (comparison), namely if a_k =1  

This comparison is executed in every iteration of the for-loop  

k can take on the values from 1 to n (for k:=I to n), thus k can take on n values.  

Thus in total there are then n comparisons, while n is 0(n).

5 0
3 years ago
Number 10 I don't understand i
Butoxors [25]
Look for the factors of 32 which are 1,2,4,8,16,32  

you can have one row of 32, 32 rows of 1, 16 rows of 2, 2 rows of 16, 4 rows of 8, and 8 rows of 4. 

That's six different ways
5 0
3 years ago
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