All categories

3 years ago

How would the frog hop to meet the following requirements?

Mathematics

1 answer:

Anton [14]3 years ago

4 0

Answer:

He would make one hop to land on 6.

Step-by-step explanation:

He starts on 6, and hops to the opposite of the opposite of 6, which is 6.

You might be interested in

May I please receive help?

romanna [79]

Answer:

$\frac{10}{9}\pi$ yards

Step-by-step explanation:

The circumference of this circle = 2πr

= 8π

We have to find the arc length of 50°, or 50/360 times the circumference of the circle(because there is 360° in a circle)

$\frac{50}{360} * 8\pi = \\\\\frac{400\pi}{360} =\\\\ \frac{10\pi}{9}$

-Chetan K

3 0

3 years ago

A student solved 6x+4=2(x−8) in four steps as shown:

mr_godi [17]

The first thing you should do is solve the equation yourself.

1) Distribute the 2.
6x + 4 = 2x – 16

2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16

3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
4x = -12

4) Finally, divide both sides by 4
4x/4 = -12/4
x = –3

To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.

7 0

3 years ago

A manager is comparing wait times for customers in a coffee shop based on which employee is

anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

$H_0: \mu_A - \mu_B = 0$

At the alternative hypothesis, it is tested if there is difference, that is:

$H_1: \mu_A - \mu_B = 0$

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

$\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2$

$\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4$

For the distribution of differences, we have that:

$\overline{x} = \mu_A - \mu_B = 73 - 74 = -1$

$s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447$

<h3>What is the test statistic?</h3>

It is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-1 - 0}{0.447}$

$t = -2.24$

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0

2 years ago

118 + 560 is the same as<br> 100 +

Fed [463]

Answer:

578

Step-by-step explanation:

118

+560

answer:678

678-100=578

6 0

3 years ago

Read 2 more answers

A bag contains five green marbles three blue marbles and two red marbles if two consecutive marbles are drawn without replacemen

iren2701 [21]

Answer:

1 / 9

Step-by-step explanation:

P(Green) = 5 / 10

P(Blue) = 3 / 10

P(Red) = 2 / 10

These are independent events as one cannot occur at the same time as the other so can multiply their probabilities together

First choice green: 5 / 10

The denominator will decrease because we arent replacing the marbles after we take one out of the bag

Second choice red: 2 / 9

5 / 10 x 2 / 9

10 / 90 = 1 / 9

3 0

3 years ago

Read 2 more answers