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ki77a [65]
1 year ago
11

The ratio of girls to boys in a a gardening club was 6:2 there were 16 boy how many are girls

Mathematics
1 answer:
marishachu [46]1 year ago
3 0

Answer:

I don't know

Step-by-step explanation:

tdhdujdjbd

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If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is
Zinaida [17]

Answer:

Step-by-step explanation:

 This is a simple proportion problems.

7 kilogram weight attache to a spring stretches  = 6 meters

 1 kilogram would stretch                                       =  6/7 m

Therefore 42 kilograms would  stretch                  = (6/7 x 42)meters

                                                                                 =  36 meters.

                                                                         

 

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%285y%20%2B%209%29%286y%20-%201%29" id="TexFormula1" title="(5y + 9)(6y - 1)" alt="(5y + 9)(6y
mestny [16]
Hey there :)

( 5y + 9 )( 6y - 1 )

We need to use FOIL to expand, that is
First Terms
Outer Terms
Inner Terms
Last Terms

     First          Outer         Inner      Last
( 5y )( 6y ) + ( 5y )( - 1 ) + 9 ( 6y ) + 9 ( - 1 )
    30y²     -        5y      +    54y   -       9

Combine, if any, the like-terms
30y² + 49y - 9
7 0
3 years ago
Read 2 more answers
Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia
Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

This last one is an unbiased estimator of the common variance \sigma^2

So on this case the degrees of freedom are given by:

df= 37+45-2=80

And the best answer is:

d. t distribution with df = 80

5 0
2 years ago
Write the equation of the line in fully simplified slope-intercept form. Y intercept is -6
irakobra [83]
The answer would be y= 2/3x -6
8 0
2 years ago
Read 2 more answers
Plz answer this!!!!!!!!!
Fed [463]

Answer:

32

Explanation:

Since you're looking for the 4th term in the sequence, go ahead and replace the <em>n</em> with 4:

 2*4^{4-2}

which is equal to

2*4^{2}

which is

2*16

and that is 32

4 0
2 years ago
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