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Finger [1]
3 years ago
5

The ability to examine the variability of a solution due to changes in the formulation of a problem is an important part of the

analysis of the results. This type of analysis is called ________ analysis.
Mathematics
1 answer:
never [62]3 years ago
6 0

Answer:

sensitivity analysis

Step-by-step explanation:

The ability to examine the variability of a solution due to changes in the formulation of a problem is an important part of the analysis of the results. This type of analysis is called Sensitivity analysis.

It helps us figure out the robustness of a system or model in the presence of an uncertainty

It also increases the relationship between the inputs and outputs from the system or model

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8 ^ x * 16 ^ x - 1 equals 1​
Lana71 [14]

Answer:

{8}^{x}  \times  {16}^{x }  - 1 = 1 \\  {2}^{3x}  \times  {2}^{4x}  = 1 + 1 \\  {2}^{7x}  =  {2}^{1}  \\ 7x = 1 \\ x =  \frac{1}{7}

7 0
3 years ago
What is the y-intercept In 0-9 1-12 2-15 3-18 4-21
My name is Ann [436]

Answer:

0,9

Step-by-step explanation:

6 0
3 years ago
Assume a profitable economic well produces an average income of $23 million, while the average cost of a dry hole is $1.2 millio
bezimeni [28]

The most appropriate choice for revenue and profit will be given by-

Profit expected from a 100-well drilling program = $146.2

What is revenue and profit?

Total income generated by sale of goods and service is called revenue.

If p is the cost of producing one unit of a commodity and q is the number of units of the commodity, then the product of p and q gives the revenue.

If the revenue obtained by selling a commodity is more than the cost, difference between revenue and cost gives the profit.

Here,

Number of economic wells = 11

An economic well produces an average income of $23

Revenue obtained = $$(23 \times 11)

Number of dry wells = 100 - 11

                                  = 89

Average cost of a dry hole is $1.2 million

Cost of 89 dry holes = $$(89 \times 1.2)

                                   = $106.8

Profit = Revenue - cost

         = $(253-106.8)

         = $146.2

Profit  expected from a 100-well drilling program = $146.2

To learn more about revenue and profit, refer to the link:

brainly.com/question/25623677

#SPJ10

Complete Question

The diagram has been attached

Assume a profitable economic well produces an average income of $23 million, while the average cost of a dry hole is $1.2 million. How much profit can be expected from a 100-well drilling program?

7 0
1 year ago
Someone help and makes sure the answer is right please :)
oksian1 [2.3K]

Answer:

x=6

Step-by-step explanation:

Since the two lines  are  parallel, the angles are congruent to each other.

-4+14x=80

14x=84

x=6

Hope  this helps!

4 0
3 years ago
Read 2 more answers
Each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard d
Verdich [7]

Answer:

(a) Between 27 and 31 pounds per month = 0.62465

(b) More than 30.2 pounds per month = 0.1357

Step-by-step explanation:

We are given that each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard deviation is 2 pounds and the variable is approximately normally distributed.

<em>Let X = generation of newspaper for garbage or recycling</em>

The z-score probability distribution for normal distribution is given by;

             Z = \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population average = 28 pounds

            \sigma = population standard deviation = 2 pounds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability of household generating between 27 and 31 pounds per month is given by = P(27 pounds < X < 31 pounds) = P(X < 31 pounds) - P(X \leq 27 pounds)

   P(X < 31 pounds) = P( \frac{X-\mu}{\sigma} < \frac{31-28}{2} ) = P(Z < 1.50) = 0.93319

  P(X \leq 27 pounds) = P( \frac{X-\mu}{\sigma} \leq \frac{27-28}{2} ) = P(Z \leq -0.50) = 1 - P(Z < 0.50)

                                                             = 1 - 0.69146 = 0.30854                       

<em>{Now, in the z table the P(Z  </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 and x = 0.50 in the z table which has an area of 0.93319 and 0.30854 respectively.}</em>

Therefore, P(27 pounds < X < 31 pounds) = 0.93319 - 0.30854 = 0.62465

(b) Probability of household generating more than 30.2 pounds per month is given by = P(X > 30.2 pounds)

   P(X > 30.2 pounds) = P( \frac{X-\mu}{\sigma} > \frac{30.2-28}{2} ) = P(Z > 1.10) = 1 - P(Z \leq<em> </em>1.10)

                                                                   = 1 - 0.8643 = 0.1357

<em>Now, in the z table the P(Z  </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.10 in the z table which has an area of 0.8643.</em>

3 0
4 years ago
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