Between 0.5 and 0.6 can be an infinity.
<em><u>ex:</u></em><u /><u><em /></u><em />
0.51
0.52
0.517
0.5169889549.......
0.5999999999..........
etc.
Answer:
B. Distinct Parallel lines.
Step-by-step explanation:
Answer:
option (b) df = 1, 24
Step-by-step explanation:
Data provided in the question:
levels of factor A, a = 2
levels of factor B, b = 3
Subjects in each Sample, s = 5
n = 5 × 3 × 2 = 30
Now
df for Factor A = a - 1
= 2 - 1
= 1
df for Factor B = b - 1
= 3 - 1
= 2
df for Interaction AB = ( a - 1 ) × ( b - 1 )
= 1 × 2
= 2
df for Total = n - 1
= 30 - 1
= 29
df for error = 29 - 5
= 24
Hence,
df values for the F-ratio evaluating the main effect of factor A is 1, 24
The correct answer is option (b) df = 1, 24
Answer: 2
I'm really struggling with this concept, hoping you guys could help me out.
The pairs have been separated out and you must take out a pair of socks.
Consider these problems and provide a calculation for each:
Probability of drawing a matching pair if you randomly draw 2 socks?
Probability of drawing a matching pair if you randomly draw 3 socks?
(Repeats up to randomly drawing 5 socks)
For 2 socks I got the following:
40 possible socks * 39 other possible socks = 1560 possible combinations of socks / 2 (to remove duplicate matches) = 780
For each set of socks, there are 8. 8 * 7 (7 other socks to each being matched) = 56 possible combinations in each set of socks / 2 to remove duplicates = 28 possible combinations of socks in each set.
28 / 780 = 0.036 probability of drawing a pair when drawing 2 socks from the drawer.
Step-by-step explanation:
Answer:
Every angle is 180 degrees so 180-73=107 so 107 is your answer.
Step-by-step explanation:
