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3 years ago

Z ÷ 12 = 9 (PLEASE ANSWER QUICK)

Mathematics

2 answers:

hodyreva [135]3 years ago

6 0

Answer:

I got youuuuuuu, its 108

KiRa [710]3 years ago

5 0

Answer:

z = 108

Step-by-step explanation:

9 x 12 = 108

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Geometry question, need help.

Margaret [11]

It would be choice A

3 0

3 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

Practice solving and using literal equations.

just olya [345]

Answer: principal = $16.00

Step-by-step explanation:

P = A / (1 + rt)

P = 20 / (1+.05 x 5)

P = 20 / (1.25)

P = 16

5 0

3 years ago

Least common denominator again please lol. Sorry I keep asking so many questions, but hey, I guess it means you guys get more po

Olenka [21]

Answer:

hope it's help u

Step-by-step explanation:

$the \: lcm \: of \: 2 \: and \: 9 \: is \: 18.so \: the \: lcd \: is \: 18 \\ \frac{11}{2} = \frac{11 \times 9}{2 \times 9} = \frac{99}{18 } \\ \frac{1}{9} = \frac{ 1\times 2 }{9 \times 2} = \frac{2}{18} \\ \frac{99}{18} > \frac{2}{18}$

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3 years ago

The quotient of 1.2 added to a number and 5 is 3.6?

Nat2105 [25]

You would add 5 and 1.2 which gives you 6.2 then you add negative 3.6 which then gives you 3.6.

5 0

4 years ago

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