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mrs_skeptik [129]
2 years ago
14

Molly is excited to have fresh basil at home. She buys a basil plant that is 90 millimeters tall and puts it on her kitchen wind

owsill. A month later, the plant is 20 centimeters taller! One night, Molly wants to add some basil to her stir-fry, so she cuts off 12 centimeters. How many centimeters tall is her basil plant now?
(I'm really sorry if I'm asking to much I have some assignments which are hard please help me)
Mathematics
1 answer:
satela [25.4K]2 years ago
5 0

Answer:

Molly's basil plant is now 17 centimeters

Step-by-step explanation:

90 millimeters=9 centimeters

20cm-12cm=8cm

9cm+8cm=17cm  

hope this helped :)

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These techniques for elimination are preferred for 3rd order systems and higher.  They use "Row-Reduction" techniques/pivoting and many subtle math tricks to reduce a matrix to either a solvable form or perhaps provide an inverse of a matrix (A-1)of linear equation AX=b.  Solving systems of linear equations (n>2) by elimination is a topic unto itself and is the preferred method.  As the system of equations increases, the "condition" of a matrix becomes extremely important.  Some of this may sound completely alien to you.  Don't worry about these topics until Linear Algebra when systems of linear equations (Rank 'n')  become larger than 2.

Step-by-step explanation:

Just to add a bit more information, "Elimination" Can have a variety of other interpretations.  Elimination techniques typically refer to 'row reduction' to achieve 'row echelon form.'  Do not worry if you have not heard of these terms.  They are used in Linear Algebra when referring to "Elimination techniques"

 

Gaussian Elimination

Gauss-Jordan Elimination

LU-Decomposition

QR-Decomposition

 

These techniques for elimination are preferred for 3rd order systems and higher.  They use "Row-Reduction" techniques/pivoting and many subtle math tricks to reduce a matrix to either a solvable form or perhaps provide an inverse of a matrix (A-1)of linear equation AX=b.  Solving systems of linear equations (n>2) by elimination is a topic unto itself and is the preferred method.  As the system of equations increases, the "condition" of a matrix becomes extremely important.  Some of this may sound completely alien to you.  Don't worry about these topics until Linear Algebra when systems of linear equations (Rank 'n')  become larger than 2.

 

Substitution is the preferred method for 2 equations in 2 unknowns.  The constants are unimportant other than having a non-zero determinant.  It is always easy to find multiplicative factors using LCMs of one variable or the other to allow substitution into the other equation:

 

Example:

 

4X + 5Y = 9

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Notice that 20 is a LCM of either the X or Y variable.  So multiply the first by 4 and the second by 5 and then adding the two (Y's will drop out allowing for substitution)

 

4(4X + 5Y = 9)

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Multiplying to produce the LCM factors:

 

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Adding the equations

 

41X = 41

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Substitution into either equation yields

Y = 1

 

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