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2 years ago

I really need help on 16 and 18 I'm super confused problem because I'm tired but I really need help

Mathematics

1 answer:

Bogdan [553]2 years ago

5 0

Answer:

Hello,

Step-by-step explanation:

16)

Area of the square= 5²=25 (unit of square)

17)

Volume of the cube =3^3 =27 (unit of volume)

18)

side of the cube =5 (unit of lenght)

Volume of the cube = (5 (unit of lenght)) ^3

=125 * (unit of lenght)^3 =125 (unit of volume)

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A woman is emptying her aquarium at a steady rate with a small pump. The water pumped to a 12-in.-diameter cylindrical bucket, a

Temka [501]

Answer:

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

Step-by-step explanation:

Given that,

The diameter of cylindrical bucket = 12 in.

Depth is increasing at the rate of = 4.0 in per minutes.

i.e $\frac{dh_1}{dt}=4$

$h_1$ is depth of the bucket.

The volume of the bucket is V = $\pi r^2 h$

$=\pi \times 6^2\itimes h_1$

$\therefore V=36\pi h_1$

Differentiating with respect yo t,

$\frac{dV}{dt}=36\pi \frac{dh_1}{dt}$

Putting $\frac{dh_1}{dt}=4$

$\therefore\frac{dV}{dt}=36\pi\times 4$

The rate of volume change of the bucket = The rate of volume change of the aquarium .

Given that,The aquarium measures 24 in × 36 in × 18 in.

When the water pumped out from the aquarium, the depth of the aquarium only changed.

Consider h be height of the aquarium.

The volume of the aquarium is V= ( 24× 36 ×h)

V= 24× 36 ×h

Differentiating with respect to t

$\frac{dV}{dt}=24\times 36 \times \frac{dh}{dt}$

Putting $\frac{dV}{dt}=36\pi\times 4$

$36\pi\times 4= 24\times 36\times \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt}=\frac{36\pi \times 4}{24\times 36}$

$\Rightarrow \frac{dh}{dt}=\frac{11}{21}$

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

7 0

4 years ago

I really need help on 16 and 18 I'm super confused problem because I'm tired but I really need help ​

I really need help on 16 and 18 I'm super confused problem because I'm tired but I really need help