PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!

Mathematics

1 answer:

IrinaK [193]3 years ago

7 0

Step-by-step explanation:

i think u had done something wrong in equation

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What it 55/100 in simplest form

den301095 [7]

55/100 = (55:5)/(100:5) = 11/20

55/100 = 0.55

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3 years ago

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Complete the equation of the graphed linear function in point-slope form.

vazorg [7]

The point-slope form:
$y-y_1=m(x-x_1)$
m - slope
x₁, y₁ - the coordinates of a point

It passes through the points (1,-2) and (2,2).
$(1,-2) \\
x_1=1 \\ y_1=-2 \\ \\
(2,2) \\
x_2=2 \\ y_2=2 \\ \\
m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-2)}{2-1}=\frac{2+2}{1}=4$

$\boxed{y-(-2)=4(x-1)}$

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3 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

$from \: the \: figure \\ AB = 300 \: ft \: \: \: angle \: C = 60 \:( theta)\: degress \\ in \: triangle \: ABC \: using \: tan \: theta\\ \tan(60) = \frac{opposite \: side}{adjacent \: side} \\ \tan(60) = \frac{300}{BC} \\ \sqrt{3} = \frac{300}{BC} \\ BC = \frac{300}{ \sqrt{3} } \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\ \tan(30 ) =\frac{opposite \: side}{adjacent \: side} \\ \tan(30) = \frac{300}{BD} \\ \frac{1}{ \sqrt{ 3} } = \frac{300}{BD} \\ BD = 300 \sqrt{3} \\ CD = BD - BC \\ = 300 \sqrt{3 } - 100 \sqrt{3} \\ = (300 - 100) \sqrt{3} \\ = 200 \sqrt{3 } \\ = 200 \times 1.732 \\ = 346.4 \: ft$

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3 years ago

Latrell is comparing two job opportunities one job will pay $12 an hour and he will work 40 hour a week. The other one pays an a

Nata [24]

To compare these two jobs, you need to have a common point. In this problem, you have to solve for the annual salary of the first job and compare it with the annual salary of the second job which is already given.

$12 per hour x 40 hours per week x 48 weeks in a year = $23,040

First job’s annual salary is $23,040

Second job’s annual salary is $22,000

Therefore, the job which pays $12 an hour pays more.

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3 years ago

What is the area of a quadrilateral ABCD, if AB = 5 cm, BC = 13 cm, CD = 9 cm, DA = 15 cm, AC = 12 cm?

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