PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!

Mkey [24]

Answer:

32

Step-by-step explanation:

if you look at the diagram the dot goes up 1 each. It also makes another row which makes 4 rows total. Since 3 contains 7 dots and 3 rows we would do 8 in 4 rows. 8 x 4 is 32.

Hope this helped!

7 0

3 years ago

Read 2 more answers

Please Help ASAP!! NEED DONE QUICKLY!!

Kipish [7]

Answer:

z=t and y = 4y -- 6 for any t?

5 0

3 years ago

Divides a line segment at the middle

bazaltina [42]

Answer: Midpoint

<u>Step-by-step explanation:</u>

Midpoint is the point that is equal distance from the endpoints.

8 0

3 years ago

Nathan is going to invest in an account paying an interest rate of 1.9% compounded continuously. How much would Nathan need to i

Sliva [168]

Answer:

223 (rounded to closest one) actual answer would be 222.91479275

Step-by-step explanation:

use formula A=Pe^nt

$280 = Pe^0.019(12)

$280 = Pe^0.228, then evaluate the solution by isolating the variable and dividing each side by the factors which don't contain the variable.

P = 222.91479275

3 0

3 years ago

For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;

Dmitrij [34]

Answer:

a.

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

$ax+by=c$

Suppose integers x0 and yo satisfy the equation; that is,

$ax_0+by_0 = c$

what other values

$x = x_0+h$ and $y=y_0+k$

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

$as+bt=gcd(a,b)$

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

$a(sk) + b(tk) = gcd(a,b)k = c$

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

$a(x_1-x) + b(y_1-y)=0$

Therefore,

$a(x_1-x) = b(y-y_1)$

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

$y = y_1+r(\frac{a}{gcd(a, b)})$ for some integer r. Substituting into the equation

$a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba$

or

$x = x_1-r(\frac{b}{gcd(a, b)} )$

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

$15 = 6*2+3\\6=3*2+0$