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Arte-miy333 [17]
2 years ago
8

If a supply chain manager can reduce inventory while keeping the flow rate constant, what does little's law predict will happen

to flow time?
Business
1 answer:
ozzi2 years ago
7 0

If a supply chain manager can reduce inventory while keeping the flow rate constant, little's law predicts flow time will go down.

Little's Law is a theorem that calculates the average number of items in a stationary queuing system based on an item's average waiting time and the average number of items arriving at the system per unit of time.

The law establishes a straightforward and obvious method for evaluating the efficiency of queuing systems.

The notion is extremely important for business operations since it states that the number of items in the queuing system is determined primarily by two essential variables and is unaffected by other factors such as service distribution or service order.

Hence, the answer is that the flow time will go down.

Learn more about supply chain:

brainly.com/question/25160870

#SPJ4

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Workman Software has 8.8 percent coupon bonds on the market with 19 years to maturity. The bonds make semiannual payments and cu
OverLord2011 [107]

Answer:

current yield 8.2089552%

YTM = 8.05%

effective annual yield = 4.92%

Explanation:

(A)

current yield = C/P

coupon payment / market price

8.8/107.2 = 0.082089552 = 8.2089552%

(B)

P = \frac{C}{2} \times\frac{1-(1+YTM/2)^{-2t} }{YTM/2} + \frac{CP}{(1+YTM/2)^{2t}}

First par being the present value of the coupon payment and second the redeem of the face value at the end of the bond.

market price 107.2

face value 100

time = 19

rate 8.8%

C = annual coupon payment 100 x 8.8% = 8.8

You solve this using a financial calculation and get the semiannual rate

YTM/2 = 0.040268160

then multiply by 2 to get the annual YTM

0.040268160  x 2 =

YTM = 0.08053632 = 8.05%

(C)

Effective Annual Yield

(1+HPR)^{365/time} -1 = EAY

where:

Holding period return:

\frac{Net \: Return}{Investment} = HPR

In this case:

coupon payment + redem - investment = net return

8.8 * 19 + 100 - 107.2 = 160

160/107.2 = 1.492537313

Then

(1+HPR)^{365/time} -1 = EAY

(1+1.142537313)^{\frac{365}{19\times365}} -1 = EAY

EAY = 0.049242509 = 4.9242509%

8 0
4 years ago
Which of the following statements about the segment margin is not true? In preparing a segmented income statement, the variable
Trava [24]

Answer: The segment margin is obtained by deducting the common fixed costs that have been allocated to a segment from that segment's contribution margin

Explanation:

Segment margin is referred to the net profit or the net loss that a particular segment of a business makes. Segment margin is used to know segments that are performing well.

It is also used to know the long-run profitability of a particular segment as it shows the margin that is available after the cost has been covered by a segment.

Based on the above illustration, the statement that isn't true will be "the segment margin is obtained by deducting the common fixed costs that have been allocated to a segment from that segment's contribution margin".

This is false as segment margin is gotten after the traceable fixed costs of a segment has been subtracted from the contribution margin of that particular segment.

8 0
3 years ago
Alma owns fifty shares of common stock in Alpha Corporation. Alma also owns eighty shares of preferred stock in the same corpora
andreyandreev [35.5K]

Given the situation described above, Alma will be able to cast <u>50 votes</u>.

This is because common stock gives voting rights to shareholders. And given that Alma has 50 shares of common stocks. Therefore, he would be able to cast 50 votes.

On the other hand, preferred stocks give no voting rights to shareholders.

However, preferred shareholders have preference over a company's revenue or earnings, which implies that they are paid dividends before common shareholders.

Hence, in this case, it is concluded that the correct answer is "50 votes."

Learn more here: brainly.com/question/3518273

3 0
2 years ago
Mike has one hour to spend at the gym where he will jog, play handball and cycle. jogging uses 10 calories per minute, handball
slega [8]
Let
x = minutes used for jogging
y = minutes used for handball
z = minutes used for cycling

Th total time spent is 1 hour (60 minutes), therefore
x + y + z = 60

Because Mike jogs as long as he cycles, therefore
x = z
Therefore
2x + y = 60
or
y = 60 - 2x                 (1)

Jogging consumes 10 calories/min, handball consumes 9 calories/min and cycling consumes 12 calories/min.
The calories consumed in 60 minutes is 580, therefore
10 x + 9y + 12z = 580
Because x = z,
22x + 9y = 580          (2)

Substitute (1) into (2).
22x + 9(60 - 2x) = 580
22x + 540 - 18x = 580
4x = 40
x = 10
y = 60 - 2x = 40
z = x = 10

Answer:
10 minutes of jogging
40 minutes of handball
10 minutes of cycling.

4 0
4 years ago
A fast-food restaurant has determined that the chance a customer will order a soft drink is 0.90. The proba- bility that a custo
azamat

Answer:

(a) The probability that the order will include a soft drink and no fries is 0.45.

(b) The probability that the order will include a hamburger and fries is 0.48.

Explanation:

Let the events be denoted as follows:

S = an order of soft drink

H = an order of hamburger

F = an order of french fries.

Given:

P (S) = 0.90

P (H) = 0.60

P (F) = 0.50

(a)

It is provided that the event of ordering a soft drink and fries are independent.

If events A and B are independent then the probability of event (A ∩ B) is:

P(A\cap B)=P(A)\times P(B)

Compute the probability that the order will include a soft drink and no fries as follows:

P(S\cap \bar F)=P(S)\times P(\bar F)\\=P(S)\times[1-P(F)]\\=0.90\times (1-0.50)\\=0.45

Thus, the probability that the order will include a soft drink and no fries is 0.45.

(b)

It is provided that the conditional probability that a customer will order fries given that he/she has already ordered a hamburger as, P (F|H) = 0.80.

The conditional probability of an event B given another event A has already occurred is:

P(B|A)=\frac{P(A\cap B}{P(A)}

Compute the probability that the order will include a hamburger and fries as follows:

P(F|H)=\frac{P(H\cap F)}{P(H)}\\P(H\cap F)=P(F|H)\times P(H)\\=0.80\times 0.60\\=0.48

Thus, the probability that the order will include a hamburger and fries is 0.48.

6 0
3 years ago
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