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lianna [129]
4 years ago
5

NEED ANSWER ASAP!!!!

Mathematics
2 answers:
Zanzabum4 years ago
8 0

Answer:

The correct answer is first option

| -6   7  |

| 17   3  |

Step-by-step explanation:

It is given two  2x2 matrices we have to find the difference ,

| -4  8   |   -  | 2     1  |

| 3   12 |       |-14  15 |

To find the difference

| -4  8   |   -  | 2     1  |   =   | (-4 -2)         (8 - 1)     |

| 3   12 |       |-14  15 |       |  (3 - -14)      (12 - 15) |

 =    | -6   7  |

       | 17   3  |

Therefore the correct answer is first option

lesya692 [45]4 years ago
7 0

Answer:

1st option

Step-by-step explanation:

To find the difference of the given matrices, we just need to subtract the corresponding elements of the two matrices as shown below:

\left[\begin{array}{cc}-4&8\\3&12\end{array}\right] -\left[\begin{array}{cc}2&1\\-14&15\end{array}\right] \\\\ \\ =\left[\begin{array}{cc}-4-2&8-1\\3-(-14)&12-15\end{array}\right]\\\\ \\ =\left[\begin{array}{cc}-6&7\\17&-3\end{array}\right]

Thus, 1st option gives the correct answer

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Number two please <br> ASAP
miv72 [106K]

The solutions for -5 +2x^{2} = -6x is option 3. x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of ax^{2} +bx +c =0.

So -5 +2x^{2} = -6x becomes 2x^{2} +6x-5=0.

The value of a is the coefficient of the x^{2} term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to ax^{2} +bx +c =0, we get a = 2, b = 6, and c=-5.

We have the formula x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

By substituting the known values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.

\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

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4 years ago
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