Answer: 3x - 6 (in^2)
Step-by-step explanation:
base * height / 2
=
3 ( 2x - 4) / 2 (in^2)
= 3x - 6 (in^2)
IF you are solving for d:
isolate the D, do the opposite of PEMDAS.
-d/6 + 12 = -7
(subtract 12 from both sides)
-d/6 + 12 (-12) = -7 (-12)
-d/6 = -19
(multiply 6 to both sides)
-d/6(6) = -19(6)
-d = -19(6)
-d = -144
-d/-1 = -144/-1
d = 144
hope this helps
Answer:
x=2i, -2i
Step-by-step explanation:
Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
Answer:
where 
= 2
Step-by-step explanation:
512/-8 = -64
difference of n = 3
![\sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
where = 2
