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2 years ago

13

Marlon’s TV plan costs $49.99 per month plus $5.49 per first-run movie. How many first-run movies can he watch if he wants to ke

ep his monthly bill to be a maximum of $100?

1 answer:

Igoryamba2 years ago

6 0

The maximum number of first-run movies Marlon can watch is 9.

In arithmetic, an inequality is a relation that makes a non-same comparison among two numbers or different mathematical expressions. It's miles used most customarily to compare two numbers on the number line by their size.

Inequality, In arithmetic, is a statement of an order courting—more than, extra than or equal to, less than, or less than or equal to—among two numbers or algebraic expressions.

The TV plan is $49.99 per month plus $5.49 per first-run movie.

The maximum monthly TV bill is $100.

If let a total number of the first-run movies he can watch is n.

Since the monthly TV bill is not more than $100.

Therefore, $49.99 per month plus $5.49 per first-run movie should be less than or equal to $100.

So, the value of n is 9.

Learn more about inequality here brainly.com/question/11613554

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1 Select the correct answer. Multiply the binomials: (3x + 4)(5x - 2) A.15x2 + 20x-8b. 15x2 + 14x-8 c. 15x2- 14x-8 D. 15x2+ 14x8

leonid [27]

Multiply the binomials:

(3x + 4)(5x - 2)

$\begin{gathered} =3x(5x\text{ - 2) + 4(5x - 2)} \\ =15x^2\text{ - 6x + 20x - 8} \\ =15x^2\text{ + 14x - 8} \end{gathered}$

Final answer

Option B is the final answer

3 0

1 year ago

Yesterday 160 guest at a hotel called for room service, and 240 guest did not called for room service. What is the percentage of

Dmitry [639]

160/400
80/200
40/100
C

8 0

3 years ago

20x^2-30=4x solve for x

ankoles [38]

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given $20x^{2}-30=4x$

Subtract 4x from both sides

$20x^{2}-4x-30=0$

Since we can factor out 2 from whole equation, let's factor out 2.

$2(10x^{2}-2x-15)=0$

Divide with 2 on both sides

$10x^{2}-2x-15=0$

We got the quadratic equation, we can solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}$

$x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}$

$x=\frac{2\pm\sqrt{604} }{20}$

$x=\frac{2\pm2\sqrt{151}}{20}$

$x=1.3288or-1.1288$

8 0

3 years ago

Read 2 more answers

What is [[3^3-7)·5)/10]+((1+3+6+9)-)]

yanalaym [24]

Answer:

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Step-by-step explanation:

As far as I am able to observe from the statement of your question, the expression is:

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

So, lets solve this expression, which anyways would clear your concept

Considering the expression

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1$

Lets first solve $\left(3^3-7\right)\frac{5}{10}$

As $3^3=27$

$=\frac{5}{10}\left(27-7\right)$

$=\frac{1}{2}\left(27-7\right)$

$=20\cdot \frac{1}{2}$

$=10$

So,

$\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1 = 10+1+3+6+9-1$

= $28$

Therefore,

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Keywords: Expression solving

Learn more about solving expression from brainly.com/question/4687406

#learnwithBrainly

7 0

3 years ago

a truck can be rented from company A for $120 a day plus $0.40 per mile. Company B charges $70 a day plus $0.50 per mile to rent

pshichka [43]

<span>The answer is 500 miles.
</span>
So how you go about this problem is to first write an equation for how much each company will cost.
For Company A, it costs $120 plus some more.
The some more part can just be written as .4x where x is the number of miles
(2 miles = .4+.4 = .4(2) =.8)
So for if the cost for Company A is "A"
$A=120+.4x$

Do the same thing for Company B but with the different numbers
<span> $B=70+.5x$
</span>
Find the number of miles in a day at which the rental costs for Company A and Company B are <span>the same</span>
"The same" here means equal so set the two equations equal to each other (that means the cost of Company A=the cost of Company B or A=B)

$A=B$
$120+.4x=70+.5x$

Now use algebra to solve for x
<span> $120+.4x=70+.5x$
</span><span> $50+.4x=.5x$
</span><span> $50=.1x$
</span> $\frac{50}{.1} = \frac{.1x}{.1}$
<span> $500=x$
</span>
The answer is 500 miles.

8 0

3 years ago