Question

20x^2-30=4x solve for x

Answer 1

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given $20x^{2}-30=4x$

    Subtract 4x from both sides

         $20x^{2}-4x-30=0$

Since we can factor out 2 from whole equation, let's factor out 2.

         $2(10x^{2}-2x-15)=0$

Divide with 2 on both sides

         $10x^{2}-2x-15=0$

We got the quadratic equation, we can solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}$

$x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}$

$x=\frac{2\pm\sqrt{604} }{20}$

$x=\frac{2\pm2\sqrt{151}}{20}$

$x=1.3288or-1.1288$

Answer 2

Mmmm let me think about it