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erma4kov [3.2K]
1 year ago
15

In ipv4, datagram fragment might be fragmented again at the next router. re-assembly of these sub-fragments is handled by?

Computers and Technology
1 answer:
s2008m [1.1K]1 year ago
5 0

In IPv4, the following router could fragment the datagram fragment once more. This sub-fragment reassembling is done by the first router.

<h3>What is ipv4?</h3>
  • The fourth iteration of the Internet Protocol is known as IPv4.
  • The Internet and other packet-switched networks use it as one of its primary core protocols for internetworking.
  • The first production-ready release of IPv4 was made available on the SATNET in 1982 and the ARPANET in January 1983.
  • A protocol for usage on packet-switched Link Layer networks is the Internet Protocol version 4 (IPv4) (e.g. Ethernet).
  • A capacity of roughly 4.3 billion addresses is offered by IPv4.

To learn more about ipv4, refer to:

brainly.com/question/28432421

#SPJ4

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What were the important developments that occurred in photography that facilitated the creation of motion pictures? Two critical
8_murik_8 [283]

Answer:

"A moving picture is an illusion that makes a still photo seem to move. The basic principal behind motion pictures is the fast transition between one picture to the next, almost creating a seamless transition. A flip-book is a good example of this. Another example would be film used for old movies. The film contains negatives of an image which when light is shined through creates a "shadow" of the image. If you quickly transition the film from one image to the next you end up a motion picture."

Explanation:

7 0
3 years ago
3.18: Pizza Pi Joe’s Pizza Palace needs a program to calculate the number of slices a pizza of any size can be divided into. The
alina1380 [7]

Answer:

#program in python.

#variables

slice_area=14.125

pi=3.14159

#read diameter

d=int(input("Enter diameter of pizza:"))

#area of pizza

area=pi*(d/2)*(d/2)

#number of slice

no_slice=int(area/slice_area)

#print slice

print("total silce are:",no_slice)

Explanation:

Declare and initialize a variable "slice_area" with 14.125 which is the area of a pizza slice.Initialize a variable "pi" with 3.14159.Then read the diameter of pizza.Find the area of pizza as "area=pi *d/2*d/2".Divide the total area with area of pizza slice.This will be the number of slice.

Output:

Enter diameter of pizza:20                                                                                                

total silce are: 22

6 0
3 years ago
Using productivity software ensures that the end product will look professional. Please select the best answer from the choices
borishaifa [10]

Answer:

False

Explanation:

5 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
The following code would include _______.
julia-pushkina [17]

Answer:

Option d is the correct answer for the above question

Explanation:

  • The above question asked about the result of the above question code, which has the query of two tables and their primary key is matched in the where class.
  • The Customer_T table has a primary key "CustomerID" and the Order_T has a foreign key "Customer_ID" and that both are matched in the where clause.
  • So the above query fetches that result in which the records match both the table. Hence Option d is the correct answer for the above question while the other is not because another option is not to get by the result of the above query.
8 0
3 years ago
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