Sketch an angle theta in standard position such that theta has the least possible positive measure and the point (-2, Square roo
1 answer:
A sketch of the angle is attached and the six trigonometric functions for each angle are;
sinθ = -½
cosθ = -(√3)/2
tanθ = (√3)/3
cscθ = -2
secθ = -(2√3)/3
cotθ = √3
<h3>How to find the trigonometric ratios?</h3>
We can use the unit circle to figure out the trigonometric functions of θ.
Both the x- and y- coordinates are in the third quadrant, so θ is an obtuse angle (210°), as seen in the figure below.
An angle in standard position is an angle measured with respect to the +x semi-axis. In this question we must derive the six trigonometric functions from the distances between a given point and the origin. The trigonometric functions are described below:
sinθ = -2/4 = -½
cosθ = (-2√3)/4 = -(√3)/2
tanθ = -2/(-2√3) = 1/√3 = (√3)/3
cscθ = 1/sin θ = 1/-½ = -2
secθ = 1/cosθ = 4/(-2√3) = -2/√3 = -(2√3)/3
cotθ = 1/tan θ = -2√3/(-2) = √3
Read more about Trigonometric ratios at; brainly.com/question/10167729
#SPJ1
You might be interested in
See Quadratic Formula and Determinant's/Delta's formula
