Given:
The expression is:
To find:
The integration of the given expression.
Solution:
We need to find the integration of .
Let us consider,
![[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ccos%202x%3D2%5Ccos%5E2x%2C1-%5Ccos%202x%3D2%5Csin%5E2x%5D)
![\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Ctan%20%5Ctheta%20%3D%5Cdfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D%5Cright%5D)
It can be written as:
![[\because 1+\tan^2 \theta =\sec^2 \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ctan%5E2%20%5Ctheta%20%3D%5Csec%5E2%20%5Ctheta%5D)
Therefore, the integration of is .
X + 4/5 = 11
x = 11 - 4/5
x = 55/5 - 4/5
x = 51/5 or 10 1/5
or u can do it this way..
x + 4/5 = 11.....multiply everything by common denominator of 5
5x + 4 = 55
5x = 55 - 4
5x = 51
x = 51/5 or 10 1/5
X = - 1/2
In other way is x = -0.2 , x = -5^-1
Since a cube has 6 sides, we can divide 294 by 6, so we have the area of one side. Since it is a cube, we can just square root that, and you get 7 cm.
