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kicyunya [14]
1 year ago
9

A circular test track for cars has a circumference of 3.7 km. A car travels around the track from the southernmost point to the

northernmost point.
What distance does the car travel?
Express your answer with the appropriate units.
Mathematics
1 answer:
Goryan [66]1 year ago
5 0

Answer:

  1.85 km

Step-by-step explanation:

You want the length of half the circumference of a circular track with a circumference of 3.7 km.

<h3>Semicircle</h3>

The extreme points on a circle are at opposite ends of a diameter. The distance along the circle from one of those points to the other is half the total circumference of the circle.

Half the length of the 3.7 km test track is ...

  (3.7 km) × (1/2) = 1.85 km

The distance the car travels is 1.85 km.

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
The lenght of a rectangle is 2 units more than the width. The area of the rectangle is 48 units. What is the length, in units, o
LenKa [72]

Answer:

The length of this rectangle is 6 units.

Step-by-step explanation:

Let the width of the rectangle be x.

x • (x+2) = 48

x^2+2x=48

x^2+2x-48=0

x^2 - 6x + 8x - 48

x(x-6) 8(x-6)

(x+8)(x-6)

x=-8,6

3 0
3 years ago
Read 2 more answers
Betty started a health and fitness program. So far, she has lost a total of 8 pounds. She is losing an average of one-fourth of
Arturiano [62]

Answer:

12 pounds

Step-by-step explanation:

1/4*16/1=4

4+8=12

8 0
3 years ago
Read 2 more answers
Your+required+return+is+14%. +should+you+accept+a+project+with+the+following+cash+flows
PtichkaEL [24]

By using an excel spreadsheet and IRR function, the cross over rate = 14.85%

Year           Cash Flow (A)           Cash Flow (B)

0                    -58,000                   -58,000

1                      34,000                     21,200

2                     28,000                     25,200

3                     20,000                     30,000

4                      13,600                     25,200

<h3>What is the IRR for each of these projects?</h3>

using an excel spreadsheet and the IRR function:

Project A's IRR = 28.3%

Project B's IRR = 25.7%

(b) If you apply the IRR decision rule, which project should the company accept?

Project A (its IRR is higher)

Requirement 2:

(a) Assume the required return is 14 percent. What is the NPV for each of these projects?

using an excel spreadsheet and the NPV function:

Project A's NPV = $14,921.37

Project B's NPV = $15,156.64

(b) Which project will you choose if you apply the NPV decision rule?

Project B (its NPV is higher)

Requirement 3:

(a) Over what range of discount rates would you choose Project A?

higher than 14.85%

(b) Over what range of discount rates would you choose Project B?

lower than 14.85%

(c) At what discount rate would you be indifferent between these two projects?

crossover rate calculation

Year           Cash Flow (A)           Cash Flow (B)       differential amount

0                    -58,000                   -58,000                       $0

1                      34,000                     21,200                     $12,800

2                     28,000                     25,200                     $2,800

3                     20,000                     30,000                  -$10,000

4                      13,600                     25,200                   -$11,600

using an excel spreadsheet and IRR function, the cross over rate = 14.85%

To know more about IRR function follow

brainly.com/question/24765495

#SPJ4

6 0
2 years ago
A
Tanzania [10]

Answer:

$45.50

Step-by-step explanation:

1. $65.00 ÷ 100 = 0.65

2. 0.65 x 30 = $19.50

3. $65.00 - $19.50 = $45.50

4 0
2 years ago
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