If you roll a die twice, what is the probability of getting a number greater than 3 on both rolls?
2 answers:
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Given:
The width of a kitchen is 4.2 metres.
Kitchen cupboard widths are 60 cm.
To find:
The number of kitchen cupboard that will fit in 4.2 metres.
Solution:
Let x be the number of kitchen cupboard that will fit in 4.2 metres.
Width of 1 cupboard = 60 cm
Width of x cupboards = 60x cm
We know that, 1 m = 100 cm.
Width of a kitchen = 4.2 metres
= 4.2×100 cm
= 420 cm
Now, the width of the x cupboards is equal to width of the kitchen.
Therefore, the number of kitchen cupboard that will fit in 4.2 metres is 7.
Honestly I can see an argument for 7 shelves or for 8 shelves.
When you do the calculation;
You get 7.15 shelves. Clearly you cannot have .15 of a shelf so the logician in me wants to say you need 8 shelves!
But if the assignment is aimed estimation skills, (Which is what I assume is being implied by the title of the assignment), then the easier calculation of
is probably what the teacher was hoping for.
You might have been accidentally been calculating
. Remember division is NOT communitive! i.e.
.
From the image;
The first step was to see that 59 can not go into 4..resulting in the zero above the 4, multiplying 0 by 59 and subtracting 0 from 4.
The second step begins by bringing down the 2, seeing that 59 can not go into 42..resulting in the zero above the 2, multiplying 0 by 59 and subtracting 0 from 42.
The third step begins by bringing down the 2, seeing that 59 can go into 422 7 times (I tested this on the right by a short multiplication problem)..resulting in the 7 above the 2, multiplying 7 by 59 and subtracting 413 from 42.
This process continues....
When you do the calculation;
But if the assignment is aimed estimation skills, (Which is what I assume is being implied by the title of the assignment), then the easier calculation of
You might have been accidentally been calculating
From the image;
The first step was to see that 59 can not go into 4..resulting in the zero above the 4, multiplying 0 by 59 and subtracting 0 from 4.
The second step begins by bringing down the 2, seeing that 59 can not go into 42..resulting in the zero above the 2, multiplying 0 by 59 and subtracting 0 from 42.
The third step begins by bringing down the 2, seeing that 59 can go into 422 7 times (I tested this on the right by a short multiplication problem)..resulting in the 7 above the 2, multiplying 7 by 59 and subtracting 413 from 42.
This process continues....