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victus00 [196]
2 years ago
13

5p + 9c = p for c Help out with this problem

Mathematics
2 answers:
maria [59]2 years ago
6 0

SOLVING

<u>=================================================================</u>

First you need to subtract by 5P both sides

9c=p-5p

and combine like terms.

9c=-4p

Next divide 9 to  both sides

c=\frac{-4p}{9}

c=-\frac{4p}{9}

Learn more;work harder

#Carryonlearning

<u>==============================================================</u>

Rom4ik [11]2 years ago
5 0

Answer:

Step-by-step explanation:

5p + 9c = p

9c = p - 5p

9c = -4p

c = -4p/9

c= \frac{-4p}{9}

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What is the simplified form of the expression? q^33/4/q^8
miss Akunina [59]
Use:\dfrac{a^n}{a^m}=a^{n-m}\\\\\dfrac{q^{\frac{33}{4}}}{q^8}=q^{\frac{33}{4}-8}=q^{8\frac{1}{4}-8}=q^\frac{1}{4}

Answer: A. q^1/4
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4 years ago
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What is d equal to? 3(2d-8)=11d-18(d-3)
never [62]

Answer:

d = 6

Step-by-step explanation:

3(2d-8)=11d-18(d-3)

6d - 24 = 11d -18d +54

6d-11d+18d = 24+54

13d = 78

d = 6

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4 years ago
2 to the 12th power = 4,096. How many other whole numbers can you raise to a power to get 4,096! Explain or show your reasoning.
Sonja [21]

Answer:

Other whole numbers that can be raised to a power to get 4,096 are  4, 8, 16 and 64

Step-by-step explanation:

Given;

2¹² = 4096

Other whole numbers that can be raised to a power to get 4,096 are obtained as follows;

if \ (a^x)^y = a^{xy}\\\\ (2^2)^6 = 4,096\\\\(4)^6 = 4,096\\\\Thus, \ the \ first \ whole \ number \ is  \ 4\\\\(2^3)^4 = 4,096\\\\(8)^4 = 4,096\\\\Thus, \ the \ second \ whole \ number \ is  \ 8\\\\(2^4)^3 = 4,096\\\\(16)^3 = 4,096\\\\Thus, \ the \ third \ whole \ number \ is  \ 16\\\\(2^6)^2 = 4,096\\\\(64)^2 = 4,096\\\\Thus, \ the \ fourth \ whole \ number \ is  \ 64

Therefore, Other whole numbers that can be raised to a power to get 4,096 are  4, 8, 16 and 64

7 0
3 years ago
the length of a rectangle is 3 cm less than the width. the area is 54cm^2. what is the length and the width of the rectangle?
GrogVix [38]

Answer:

The length of the rectangle is 6cm while the width is 9cm

Step-by-step explanation:

Here, we are interested in calculating the length and width of the rectangle.

Let the length of the rectangle be x cm

We are told that the length is 3 cm

less than the width, this means that the width is (x + 3) cm

The area of the rectangle is 54cm^2

Mathematically;

Area of rectangle = L * B

Thus;

x(x + 3) = 54

x^2 + 3x = 54

x^2 + 3x -54 = 0

x^2 + 9x -6x -54 = 0

x(x + 9 ) -6(x + 9) = 0

(x -6)(x + 9) = 0

x -6 = 0 or x+ 9 = 0

x = 6 or -9

Since length cannot be negative we choose x = 6cm

But width = x + 3 = 6 + 3 = 9cm

6 0
3 years ago
Solve for x:<br> 4(1 – x) + 2 x = -3( x + 1)
valentinak56 [21]

Answer:

<u>4(1 – x) + 2 x = -3( x + 1)</u>

first do 4 time 1= 4

then do 4 times x =4x

now the equation should look like this

4-4x+2x=-3(x+1)

then do the other side of the equation

-3(x+1)

=-3x-3

Now collect the like terms:

-4x-2x

now the equation should look like this

4-2x=-3x-3

now add 3x add on both sides

4-2x+3x=-3

put the 4 on the other side

-2x+3x=-3-4

now again collect the like terms (-2x+3x=1 which is just x and -3-4 =-7)

x=-7

answer

x=-7

3 0
3 years ago
Read 2 more answers
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