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3 years ago

7

7/10 as a sum of fraction.

2 answers:

KiRa [710]3 years ago

6 0

There are both 0.7 or 0.70 for ur actual answer.

nalin [4]3 years ago

4 0

0.7 or 0.70 can be your answer

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The first three steps for solving the quadratic equation by completing the square are shown. Fill in the missing number in the l

gulaghasi [49]

Completing the square is done as follows:

1. Write the equation in a way that the constants are in the right side while the terms with x are on the left.
<span>9x2 +54x = 7
</span>
2. Make sure that the coefficient of the x^2 term is 1.
<span>9(x2 + 6x) = 7
</span>
3. Adding a term to both sides that will complete the square in the left side. This is done by dividing the coefficient of the x term by 2 and squaring it. Note: The same amount should be added to the right side to balance the equation.
<span>9(x2 + 6x + 9) = 7 + 81

9(x+3)^2 = 88
</span>

5 0

3 years ago

Read 2 more answers

1) Which variable did you plot on the x-axis, and which variable did you plot on the y-axis?

Liula [17]

Answer:

Step-by-step explanation:

This question is too difficult

3 0

2 years ago

24 POINTS!!!!!!

nika2105 [10]

5x - 2 equivalent to to 2x−2+3x

answer is B. 2x−2+3x

7 0

3 years ago

A random sample of 300 circuits generated 13 defectives. Use the data to test the hypothesis Upper H Subscript 0 Baseline colon

____ [38]

Complete Question

A random sample of 300 circuits generated 13 defectives. a. Use the data to test

$H_o : p = 0.05$

Versus

$H_1 : p \ne 0.05$

Use α = 0.05. Find the P-value for the test

Answer:

The p-value is $p-value = 0.5949$

Step-by-step explanation:

From the question we are told that

The sample size is n = 300

The number of defective circuits is k = 13

Generally the sample proportion of defective circuits is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{13}{300}$

=> $\^ p = 0.0433$

Generally the standard Error is mathematically represented as

$SE = \sqrt{\frac{p(1- p)}{n} }$

=> $SE = \sqrt{\frac{0.05(1- 0.05)}{300} }$

=> $SE = 0.0126$

Generally the test statistics is mathematically represented as

$z = \frac{\^ p - p }{SE}$

=> $z = \frac{0.0433 - 0.05 }{0.0126}$

=> $z = -0.5317$

From the z table the area under the normal curve to the left corresponding to -0.5317 is

$(P < -0.5317 ) = 0.29747$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z < -0.5317 )$

=> $p-value = 2 * 0.29747$

=> $p-value = 0.5949$

3 0

3 years ago

Pls help me on this question

Step2247 [10]

Answer:H

Step-by-step explanations

Hope this helpes

4 0

3 years ago