We conclude that the linear equation perpendicular to y = x/4 - 1 and that passes through (-4, 5) is y = -4*x - 11
<h3>How to find the perpendicular line?</h3>
A general linear equation is of the form:
y = a*x + b
Where a is the slope and b is the y-intercept.
Two lines are perpendicular if the slope of one line is equal to the inverse of the opposite of the other slope.
So, if we have:
y = x/4 - 1
The slope is a = (1/4)
The inverse of the opposite is:
a' = -4
Then the perpendicular line is of the form:
y = -4*x + c
Now we want this to pass through the point (-4, 5), then we must have:
5 = -4*-4 + c
5 = 16 + c
5 - 16 = c = -11
We conclude that the linear equation perpendicular to y = x/4 - 1 and that passes through (-4, 5) is y = -4*x - 11
If you want to learn more about linear equations:
brainly.com/question/1884491
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