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irakobra [83]
2 years ago
14

Find the equation of the line through (- 4, 5) which is perpendicular to the line y = x/4 - 1

Mathematics
1 answer:
iragen [17]2 years ago
4 0

We conclude that the linear equation perpendicular to y = x/4 - 1 and that passes through (-4, 5) is y = -4*x - 11

<h3>How to find the perpendicular line?</h3>

A general linear equation is of the form:

y = a*x + b

Where a is the slope and b is the y-intercept.

Two lines are perpendicular if the slope of one line is equal to the inverse of the opposite of the other slope.

So, if we have:

y = x/4 - 1

The slope is a = (1/4)

The inverse of the opposite is:

a' = -4

Then the perpendicular line is of the form:

y = -4*x + c

Now we want this to pass through the point (-4, 5), then we must have:

5 = -4*-4 + c

5 = 16 + c

5 - 16 = c = -11

We conclude that the linear equation perpendicular to y = x/4 - 1 and that passes through (-4, 5) is y = -4*x - 11

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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