
Solution:
Given expression:

To solve the given expression:
First simplify: 

Cancel the common factor (w + 5).

Now substitute this in the given expression.

Multiply the fractions 

Factor the denominator 
Cancel the common factor 2(w – 5).

Factor the numerator 

Cancel the common factor (w – 2).


(a) 8(4x+3) > -1 + 7x
32x + 24 > -1 + 7x
32x - 7x > -1 -25
25x >-26
x > -26/25
(b) 167 < 6 + 7(2 - 7r)
167 < 6 + 14 - 49r
49r < 6 + 14 - 167
49r < - 147
r < - 3
(c) 8x + 40 > -8 ( 1 - 7x)
8x + 40 > -8 + 56x
56x - 8x < 48
48x < 48
x < 1
(d)5( 6 + 3r) + 7 > 127
30 + 15r + 7 > 127
15r > 127 - 37
15r > 90
r > 6
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so

- The length of the fencing is 80 meters, so

Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:

Then substitute for y in the first:

b) To maximize A, find the zero of the first derivative:

So y = (80-40)/2 = 20 meters.
X + y = 90 because the 2 angles add up to 90
Now m < x = five times m < y, so x = 5y or y = x/5
so the last choice is the correct one.