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bulgar [2K]
4 years ago
12

If 15 is 25% of a value, what is that value?

Mathematics
2 answers:
slava [35]4 years ago
5 0
The value is 60 because 25% is 1/4 of 100%
So you just do 15*4 to get 60
vladimir2022 [97]4 years ago
4 0
That value is 60 because 15 is 1/4 of 60, and 25% is 1/4 of 100
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Operations with rational expressions
Scorpion4ik [409]

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

Solution:

Given expression:

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}

To solve the given expression:

First simplify: \frac{50-2 w^{2}}{3 w^{2}+9 w-30}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}

Cancel the common factor (w + 5).

                      $=-\frac{2(w-5)}{3(w-2)}

Now substitute this in the given expression.

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}

Multiply the fractions \frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}

Factor the denominator 3(w-2)(6 w-30) =18(w-2)(w-5)

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}                        

Cancel the common factor 2(w – 5).

                               $=-\frac{w^{2}+5 w-14}{9(w-2)}

Factor the numerator w^{2}+5 w-14=(w-2)(w+7)

                               $=-\frac{(w-2)(w+7)}{9(w-2)}

Cancel the common factor (w – 2).

                               $=-\frac{w+7}{9}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

3 0
3 years ago
Shawna has $435.15 in her savings account. Which of these numbers has a 1 with a value that is 1/10 the value of the 1 in $435.1
Margaret [11]
434.15 the 1 in this equals 1/10
5 0
3 years ago
NEED HELP ASAP GIVING BRAINLIST!!!!!!!
Shtirlitz [24]

(a) 8(4x+3) > -1 + 7x

32x + 24 > -1 + 7x

32x - 7x > -1 -25

25x >-26

x > -26/25

(b) 167 < 6 + 7(2 - 7r)

167 < 6 + 14 - 49r

49r < 6 + 14 - 167

49r < - 147

r < - 3

(c) 8x + 40 > -8 ( 1 - 7x)

8x + 40 > -8 + 56x

56x - 8x < 48

48x < 48

x < 1

(d)5( 6 + 3r) + 7 > 127

30 + 15r + 7 > 127

15r > 127 - 37

15r > 90

r > 6

5 0
3 years ago
Can you guys help please im so confused
marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

- The area of the enclosure is length*width, so

A = x \cdot y

- The length of the fencing is 80 meters, so

2y + x = 80

Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

y = 40 - \frac12 x

Then substitute for y in the first:

A = x (40 - \frac12 x) = 40x - \frac12x^2

b) To maximize A, find the zero of the first derivative:

A'(x) = 40 - x = 0 \implies x=40

So y = (80-40)/2 = 20 meters.

8 0
3 years ago
Mariah cuts a rectangle along its diagonal. Two congruent triangles are created. The two angles created by the diagonal have a s
Savatey [412]
X + y = 90 because the 2 angles add up to 90

Now m < x = five times  m < y,    so x = 5y   or y = x/5

so the last choice is the correct one.
5 0
4 years ago
Read 2 more answers
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