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zmey [24]
2 years ago
9

What is 14+10 written as an algebraic expression?

Mathematics
1 answer:
malfutka [58]2 years ago
3 0

The mathematical statement of 14 + 10 is fourteen added to ten

<h3>What is 14+10 written as an algebraic expression?</h3>

The expression is given as:

14 + 10

The above expression is an algebraic expression, and it cannot be "rewritten" as an algebraic expression

Instead, it can be expressed as mathematical statement

The mathematical statement of 14 + 10 is fourteen added to ten

Read more about expression at

brainly.com/question/723406

#SPJ1

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What is x if a line passes though (2,5) ( x,3)
antoniya [11.8K]

Answer:

x = - 2

Step-by-step explanation:

Givens

(2,5)

(x,3)

m = 1/2

Formula

m = (y2 - y1)/(x2 - x1)

Solution

y2 = 3

y1 = 5

x2 = x

x1 = 2

1/2 = (3 - 5)/(x - 2)                 Cross multiply

1*(x - 2) = 2 (-2)                      Combine and remove the brackets.

x - 2 = - 4                               Add 2 to both sides

x = - 4 + 2

x = - 2

4 0
2 years ago
Solve for x<br> 4^5x=(1/32)^1-x
olasank [31]

x = -1

Step-by-step explanation:

{4}^{5x}  =  {2}^{2(5x)}  =  {2}^{10x}

{( \frac{1}{32}) }^{(1 - x)}  =  {2}^{ - 5(1 - x)}  =  {2}^{(5x - 5)}

or

{2}^{10x}  =  {2}^{(5x - 5)}

Since both sides have the same base, we can write

10x = 5x - 5

or

5x = -5

x = -1

5 0
3 years ago
Misha practices the guitar for 3 hours every day.
kakasveta [241]

Answer:

It is B. H = 3d

Step-by-step explanation:

I got it right :)

4 0
3 years ago
Read 2 more answers
Can someone check my answers? I'm not sure I have them all right...
Semmy [17]
<span>What is the y-intercept of the plane whose equation is 4x + 5y + z = 20?

(0, 4, 0) 


Which equation has intercepts at X(1, 0, 0), Y(0, 1, 0), and Z(0, 0, 2)?

2x + 2y + z = 2


Which equation is equivalent to x + 3y + z = 3?


4x + 12y + 4z = 12


Which of the following points lies in the plane 3x + 2y + 4z = 12?

(4, 3,2)


Hope these answer the questions. Have a nice day.</span>
3 0
3 years ago
A line that passes through (-1, 6) and the origin
zmey [24]

Answer: The equation is y = -6*x

Step-by-step explanation:

I suppose that we want to find the equation for a line that passes through the point (-1, 6) and the origin (remember that the origin is the point (0,0))

A general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (x₁, y₁) and (x₂, y₂), then the slope of the line is equal to:

a = (y₂ - y₁)/(x₂ - x₁)

Now we know that our line passes through the points (0, 0) and (-1, 6), then the slope is:

a = (6 - 0)/(-1 - 0) = 6/-1 = -6

Then our equation is something like:

y = -6*x + b

To find the value of b we can use the fact that this line passes through the point (0, 0).

This means that when x = 0, y is also equal to zero.

If we replace these values in the equation we get:

0 = -6*0 + b

0 = b

Then our equation is:

y = -6*x

7 0
3 years ago
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