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3 years ago

∠10° is complementary to which of the following angles?

Mathematics

2 answers:

Alex17521 [72]3 years ago

7 0

Answer:

Step-by-step explanation:

Complementary angles add up to 90.

So 90-10=80.

faust18 [17]3 years ago

5 0

Answer:

∠80°

Step-by-step explanation:

NOTE: Complementary is when the sum of two angles is equal to 90° degrees

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(-14 + 3/2b) - (1 + 8/2b) A.-5/2b - 11 B. 4b + 13/2 C. -15 - 5/2b D. 8b - 15

Darya [45]

(-14 + 3/2b) - (1 + 8/2b)
= -14 - 1 + 3/2b - 8/2b
= -15 - 5/2b

In short, Your Answer would be Option C

Hope this helps!

7 0

3 years ago

Read 2 more answers

Hey please answer the 3 questions attached, thank you very much!

kobusy [5.1K]

Answer:

a) negative correlation b) Diagram C (I think) c) Diagram b

Step-by-step explanation:

a) Negative= line going dow

Positive= line going up

no correlation= no line

b) the dots are to close to each other which mean it has a string correlation.

c)Its no correlation, so line should not be drawn

7 0

3 years ago

Please help needed immediately

lukranit [14]

All of them or a specific one?

5 0

3 years ago

Use 3.14 for pi. ROUND YOUR FINAL ANSWER TO THE NEAREST TENTHS PLACE!

Natasha2012 [34]

The area of the given circle is 95 square ft.

Calculation for the Area of the Circle:

It is given in the diagram that,

The diameter of the circle, d = 11 ft.

Now, we know that the radius of a circle is equal to half of the diameter.

Therefore, radius of the given circle, r = 11/2 ft.

The formula for the area of the circle is given as follows,

A = π × r²

Substituting the values, π = 3.1, and r = 11/2, we get,

A = (3.14) × (11/2)²

A = (3.14) × 30.25

A = 94.985

A ≈ 95

Hence, the area of the given circle with diameter 11 ft. comes out to be 95 ft².

Learn more about a circle here:

brainly.com/question/11833983

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7 0

2 years ago

Read 2 more answers

Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (

IrinaVladis [17]

Answer:

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14 and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = $\dfrac{9+9}{2}$

median = $\dfrac{18}{2}$

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = $\dfrac{12+13}{2}$

Median = $\dfrac{25}{2}$

Median = 12.5

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = Q3 - Q1

The interquartile range = 12.5 - 9

The interquartile range = 3.5

7 0

3 years ago