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patriot [66]
3 years ago
13

How do you solve this?

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

u put 90 was that the answer

Step-by-step explanation:

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the loudness, L, measured i in decibels (Db), of a sound intencity, I, measured in watts per square meter, is defined as L=10log
Jet001 [13]

Answer: D, 110 !!!

Step-by-step explanation:

8 0
4 years ago
if the sum of two numbers is four and the sum of their squares minus three times their product is 76, find the numbers
Sauron [17]

Answer:

Numbers =(6,-2 )

Step-by step explanation:

Given

the sum of two numbers is four and the sum of their squares minus three times their product is 76,

Let the first term =X

Second term will be=4-x

So

X^2+(4-x)^2-3x(4-x)=76

x^2+16+x^2-8x-12x+3x^2=76

5x^2-20x+16=76

5x^2-20x-60=0

5(x^2-4x-12)=0

So x^2-4x-12=0

x^2-(6-2)x-12=0

x^2-6x+2x-12=0

X(x-6)+2(x-6)=0

(X-6)(X+2)=0

X=6,-2

Let X=6 and -2 then numbers will be 6 and (4-6)=-2

6 0
3 years ago
Answer this question in the photo 18 PTS
LiRa [457]
Question - Answer
a) 1/2 L = 4
b) 1/2 L x 4 = 2
c) 5/6 x 2 = 1 4/6 L OR 1.67 L
d) 2/3 L = 3 beakers with 2/3 OR 5 beakers with 2/3 and 5/6
e) <1/3 L = 3 beakers

I believe that is the answer.
4 0
3 years ago
Type the correct answer in each box. If necessary, use /for the fraction bars
Vikentia [17]

Answer:

The experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

Step-by-step explanation:

The complete question is:

Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).

A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes.

3, 4, 5, 2, 7, 1, 3, 7, 2, 6, 2, 1, 7, 3, 6, 1, 8, 3, 5, 6

The experimental probability of rolling an odd number is _%, which is _% more than the theoretical probability.

Solution:

The possible outcomes of rolling an 8-sided die are:

S = {1, 2, 3, 4, 5, 6, 7, 8}

The odd numbers are:

Odd = {1, 3, 5, 7} = 4 outcomes

The theoretical probability of rolling an odd number is:

P_{T}(\text{Odd})=\farc{4}{8}=\frac{1}{2}=50\%

Now from the given 20 outcomes the odd values are:

Odd = {3, 5, 7, 1, 3, 7, 1, 7, 3, 1, 3, 5} = 12 outcomes

Compute the experimental probability of rolling an odd number as follows:

P_{E}(\text{Odd})=\frac{12}{20}=\frac{3}{5}=60\%

Thus, the experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

6 0
3 years ago
A researchers wants to determine the mean weight of avocados grown in Southern California. The population from which the sample
natka813 [3]

Answer: (0.465, 5.535)

Step-by-step explanation:

Formula to calculate the confidence interval (<em>when population standard deviation is unknown</em>) is given by :-

\overline{x}\pm t_{\alpha/2} \dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean.

s= sample standard deviation.

n= Sample size.

t_{\alpha/2} = critical value

By considering the given information , we have

\overline{x}=6

s=0.75

n= 9

Significance level = \alpha=0.1   [1-0.90=0.1]

By using students' t distribution -table , the critical value for 95% confidence level :

t_{\alpha/2 , n-1}=t_{0.1/2,\ 8}=1.86

[Note: degree of freedom = n-1]

Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :

6\pm (1.86) \dfrac{0.75}{\sqrt{9}}

6\pm (1.86) \dfrac{0.75}{3}

6\pm (1.86) 0.25

6\pm 0.465=(6-0.465,\ 6+0.465)=(0.465,\ 5.535)

Hence, the required confidence interval  =(0.465, 5.535)

4 0
3 years ago
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