A diagram shows a 5 cm* 5 cm* 5 cm cube.Calculate the length of the diagonal AB. Give your answer correct to 1 decimal place
1 answer:
The length of the diagonal AB of the given square is 8.660
Given that a diagram of a cube having dimensions 5×5×5 and asked to find out the length of diagonal AB(which is a body diagonal of the cube).
To calculate the body diagonal 1st we need to calculate the face diagonal via the Pythagorean theorem
Let's assume the length of the face diagonal is x
By Pythagorean theorem
Therefore, the length of the face diagonal is
Let's assume the body diagonal is y
By Pythagorean theorem
y==8.660
Therefore, The length of the diagonal AB of the given square is 8.660
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Answer and explanation is in a file. Li
nk below. Good luck!
bit.ly/3a8Nt8n
The standard form of a quadratic equation is 
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by 
, without the 9. So we can write:
, and substituting in we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
What we want is to write
First, we note that all the three terms have a factor of 3, so we factorize it and write:
Second, we notice that
Finally, distributing 3 over the two terms in the brackets we have:
Answer: