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vlabodo [156]
3 years ago
7

Which expression is equivalent to sec^2xcot^2x?

Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0
\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}


\sec^2x\cot^2x=\dfrac{1}{\cos^2x}\cdot\dfrac{\cos^2x}{\sin^2x}=\dfrac{\cos^2x}{\cos^2x\sin^2x}=\dfrac{1}{\sin^2x}
lukranit [14]3 years ago
5 0

Answer:

csc^2(x)

Step-by-step explanation:

https://socratic.org/questions/how-do-you-simplify-sec-2xcot-2x

I used this and got a 100 on my test.

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The side AB measures option 2. \sqrt{20}} units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.

where (x_{1},y_{1}) are the coordinates of the first point and (x_{2},y_{2}) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), (x_{1},y_{1}) = (4, 5) and (x_{2},y_{2}) = (2, 1). Substituting these values in the distance formula, we get

d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.

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6 0
2 years ago
Joanie watched 1 out of three of a movie in the morning
Archy [21]

Answer:

7/15

Step-by-step explanation:

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Step-by-step explanation:

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