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vlabodo [156]
3 years ago
7

Which expression is equivalent to sec^2xcot^2x?

Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0
\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}


\sec^2x\cot^2x=\dfrac{1}{\cos^2x}\cdot\dfrac{\cos^2x}{\sin^2x}=\dfrac{\cos^2x}{\cos^2x\sin^2x}=\dfrac{1}{\sin^2x}
lukranit [14]3 years ago
5 0

Answer:

csc^2(x)

Step-by-step explanation:

https://socratic.org/questions/how-do-you-simplify-sec-2xcot-2x

I used this and got a 100 on my test.

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
Solve the question below
mamaluj [8]

Answer: the scale factor is 2.5

Step-by-step explanation: hope it helps :)

7 0
3 years ago
I will love you forever if someone can help me with this
g100num [7]
It should be B. right angle and C. complementary angles
8 0
2 years ago
Which defines a circle
SIZIF [17.4K]
Circle<span> is the locus of points equidistant from a given point, the center of the </span>circle<span>. The common distance from the center of the </span>circle<span> to its points is called radius. Thus a </span>circle<span> is completely </span>defined<span> by its center (O) and radius (R): C(O, R) = O(R) = {x: dist(O, x) = R}.
Easier explanation: </span><span>A </span>circle<span> is a plane figure contained by one line such that all the straight lines falling upon it from one point among those lying within the figure are equal to one another.</span>
4 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is
GenaCL600 [577]

Answer:

The slope or incline is -5

Step-by-step explanation:

rewrite to get the form

y = ...

x - 5y = -10

- 5y = -10 -x

divide left and right if the = sign by -5 gives:

(-5/-5)y = (-1/-5)x + (-10/-5)

y = 1/5x +2

So the incline is 1/5

a perpendicular line has an incline of -1 *5/1 = -5

The slope or incline is -5

4 0
3 years ago
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