Please help! im so lost..

makkiz [27]

I think it’s 15.71

5 0

3 years ago

A hypotanuse of a right angle triangle is 13cm if one of the side of the triangle is 1cm shorter than the hypotanuse calculate t

pentagon [3]

Answer:

(H)^2=(B)^2 +(P)^2

(13cm)^2=(12cm)^2 +(P)^2

169cm^2=144cm^2 +(P)^2

169cm^2-144cm^2 =(P)^2

25cm^2 = (P)^2

Now taking square root on both sides

5cm = P

Step-by-step explanation:

4 0

3 years ago

Complete the paragraph below. The standard deviation is used in conjunction with the ______ to numerically describe distributio

Bumek [7]

Answer:

The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the distribution, while the standard deviation measures the spread of the distribution.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The mean is the average value of the measures while the standard deviation measures how spread the measures are from the mean. So

The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the distribution, while the standard deviation measures the spread of the distribution.

4 0

3 years ago

If a medium sized tree (13/27 ) casts a 39/40 sized shadow.. how big of a shadow would the full grown tree have?

erica [24]

Answer:

53\40

Step-by-step explanation:

27-13=14

39+1=40 14-1=13 13+40=53

53\40

4 0

3 years ago

Sally has a GPA of 3.35. What percentage of the students have a GPA above her GPA? Show all work. (Note: GPA is normally distrib

DaniilM [7]

The distribution lies within one of the standard of deviation of the mean so <span>68% </span>
The distribution lies within two of the standard of deviations of the mean so 95%
The distribution lies within three of the standard of deviations of the mean so 99.7%

7 0

4 years ago

Please help! im so lost..​

Please help! im so lost..