Answer:
The perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.
Step-by-step explanation:
Given : A quarter of a circle with radius labeled 2 in.
Quarter of circle means fourth part of a circle (as shown in image by shaded part).
We have to find the perimeter of this shaded quarter of circle.
Perimeter is the sum of the dimension of the given figure.
Perimeter of circle is 
Since, we are given Quarter circle so its perimeter 
Perimeter of given figure = 
Perimeter of given figure = 
Thus, the perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.
Answer:
Y = 300 + 2X
Y( in dollars)
It is a functional relationship because a change in the value of X results in a corresponding change in the value of Y. And does not involve any uncertainty.
Step-by-step explanation:
Given:
Annual fixed due = $300
Variable cost = $2 per visit
X = number of visits in a year
Y = total yearly cost.
Y = annual cost + variable cost
Y = $300 + $2×X
Y = 300 + 2X
Y( in dollars)
It is a functional relationship because a change in the value of X results in a corresponding change in the value of Y. And does not involve any uncertainty.
Answer:
11 17/21
Step-by-step explanation:
Answer:
Yes and she would have $2 left over because all the food costs $91.
Step-by-step explanation:
We should set up an equation so that everything makes sense. A calculator would be wise for this problem, but I am going to lay it out anyhow.
We should convert the mixed numbers to improper fractions to not be confused. 3 1/2 becomes 7/2 or 3.5 and 2 1/3 becomes 7/3.
From your wording, we can assume that the money Mrs. Donnelly has is either greater than or equal to $93.
Thus, we have 12*(7/3) + 18*(7/3) is equal to or greater than 93 (this is an inequality).
The math shows that the food costed 91 and so she only has $2 left.
Answer:
x = 6 , 5. For these values of x they are equal.
Step-by-step explanation:
2x² - x + 55 =(x +5)²
2x² - x + 55 = x² + 2*x*5 + 5²
2x² - x + 55 = x² + 10x + 25
2x² - x + 55 - x² - 10x - 25 = 0
2x² - x² - x - 10x + 55 - 25 = 0
x² - 11x + 30 = 0
x² -6x - 5x + 30 = 0
x(x - 6) - 5(x - 6) = 0
(x - 6)(x - 5) = 0
x - 6 = 0 ; x - 5 = 0
x = 6 ; x = 5
