The answer would be D- looks. All the other options are nouns and adjectives.
It suppose to be like 20.21
Answer:
The intensity on a screen 70 ft from the light is 1.728 foot candle.
Step-by-step explanation:
Given that,
The magnitude of intensity
of light varies inversely as the square of the magnitude of distance D from the source.
That is

Then,

Given that,
The magnitude of intensity of illumination on a screen 56 ft from a light is 2.7 foot-candle.
Here,
=2.7 foot-candle,
= 56 ft
=?,
= 70 ft.




foot-candle
The intensity on a screen 70 ft from the light is 1.728 foot candle.
Answer: 12 claps per second
Step-by-step explanation: divide both by 60 and yield 12 times -1 second