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2 years ago

Combine and simplify these radicals. √3-√16 A 3√4 B 3√16 C 16√3 D 4√3

Mathematics

1 answer:

Tom [10]2 years ago

8 0

Answer:

A 3√4

Step-by-step explanation:

The 3 stays and 16 gives you 4 and 4 becomes positive

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Please help me on this question<br> thank u

mafiozo [28]

System of equations:
w=(3/2)*h (1)
w*h=54 area (2)

w=54/h substitute into (1)
54/h=3h/2
3h²=54*2
h²= 36 (we take only positive solution)
h = √36=6
h=6 in.
w=(3/2)*h=(3/2)*6= 9
w=9 in.
correct answer is D

5 0

3 years ago

Consider all rectangles with an area of 200m^2. Let x be the length of one side of such a rectangle. Find the dimensions of a re

Katarina [22]

Answer: Answer in Photo

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2 years ago

Peyton is building a model tower using plastic bricks. The height of the tower is proportional to how many layers of bricks he u

Alex777 [14]

75 layers

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(120*15)/24 = x
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3 years ago

3(2x+x)/6 > 1/3x+2 solve for x

tangare [24]

1)Find all the like terms=3x3x/6>1/3x+2

2)Multiply both sides by six=9x>2x+12

3)Move the variables to the left side and change the sign=9x-2x>12

4)Find the like terms=7x>12

5)Divide by sides by seven=x>12/7

6)Your answer is x>12/7

I hope this helps! :)

4 0

3 years ago

Peter walked 10m from X to Y on bearing 020° and then he turned and walked 20m to Z with bearing 140° of Z from Y. Find the dist

seraphim [82]

Answer:

17.32m ; 110°

Step-by-step explanation:

Distance between X and Z

To calculate the distance between X and Z

y^2 = x^2 + z^2 - (2xz)*cosY

x = 20, Z = 10

y^2 = 20^2 + 10^2 - (2*20*10)* cos60°

y^2 = 400 + 100 - (400)* 0.5

y^2 = 500 - 200

y^2 = 300

y = sqrt(300)

y = 17.32m

Bearing of Z from X:

Using cosine rule :

Cos X = (y^2 + z^2 - x^2) / 2yz

Cos X = (300 + 100 - 400) / (2 * 20 '*10)

Cos X = 0 / 400

Cos X = 0

X = cos^-1 (0)

X = 90°

Bearing of Z from X

= 20° + X

= 20° + 90°

= 110°

3 0

3 years ago