I found out that putting your phone on airplane mode will charge it faster
Answer:
#include<iostream>
using namespace std;
int lcm(int m, int n) {
int a;
a = (m > n) ? m: n;
while (true) {
if (a % m == 0 && a % n == 0)
return a;
++a;
}
}
int gcd(int m, int n) {
int r = 0, a, b;
a = (m > n) ? m : n;
b = (m < n) ? m : n;
r = b;
while (a % b != 0) {
r = a % b;
a = b;
b = r;
}
return r;
}
int main(int argc, char **argv) {
cout << "Enter the two numbers: ";
int m, n;
cin >> m >> n;
cout << "The LCM of two numbers is: " << lcm(m, n) << endl;
cout << "The GCD of two numbers is: " << gcd(m, n) << endl;
return 0;
}
Explanation:
The execution speed of machine language is faster than the execution speed of other languages. Machine or assembly language will execute the fastest as compared to high-level languages. No other language can execute faster than Machine language since instructions are directed straight to the CPU. Other high-level languages often add some non-zero amount of overhead to the execution time, thus, causing some delay.
Answer:
(c) the dynamic type of reference will determine which of the methods to call.
Explanation:
Polymorphism in Object Oriented Programming typically means the same method name can cause different actions depending on which object it is invoked on. Polymorphism allows for dynamic binding in that method invocation is not bound to the method definition until the program executes.
So in the case of Animal superclass and Mammal subclass, both having a method called eat() with identical signatures and return types, depending on which reference, the correct method eat() will be called dynamically upon execution.
For example, if we have the following;
================================
<em>Mammal mammal = new Animal();</em>
<em>mammal.eat()</em>
================================
The eat() method that will be called is the one in the Mammal subclass.
However, if we have;
================================
<em>Animal animal = new Animal();</em>
<em>animal.eat()</em>
================================
The eat() method of the Animal superclass will be called.
