What can you use to make sure that you have no errors in Word Online?

Nadia's productivity at work is being hurt due to the large quantity of unwanted e-mail she receives. What steps can she take to

anastassius [24]

Answer:

Hi,

The best option in the list is stop posting her e-mail address on newsgroups.

Explanation:

Unwanted e-mail is categorized as a spam email.These emails can not be entirely avoided because we use the Internet thus it is recommended that you filter them.A program called my email client can help to filter spam though in some cases, it might not be effective.

The techniques Nadia can employ in this case is to hidden her email address when visiting newsgroups.News groups are forums online where people discuss certain topic.Avoid publishing the email in these web sites can hide her tackle this problem. Additionally, Nadia could train the filter serach feature in her email box through repoting such emails using the report button present, avoid responding/openning spam or use a third party program to track spam emails and block them.

Wish you Luck!

8 0

3 years ago

Which is a benefit of owning a desktop computer instead of a laptop?

Setler79 [48]

B) a desktop is less likely to be stolen or damaged

4 0

4 years ago

Read 2 more answers

Two numbers are given (numbers are entered from the keyboard). If both numbers are positive, then output their sum, if both numb

AleksAgata [21]

Answer:

The program in Python is as follows:

num1 = int(input())

num2 = int(input())

if num1 >=0 and num2 >= 0:

print(num1+num2)

elif num1 <0 and num2 < 0:

print(num1*num2)

else:

if num1>=0:

print(num1**2)

else:

print(num2**2)

Explanation:

This gets input for both numbers

num1 = int(input())

num2 = int(input())

If both are positive, the sum is calculated and printed

if num1 >=0 and num2 >= 0:

print(num1+num2)

If both are negative, the products is calculated and printed

elif num1 <0 and num2 < 0:

print(num1*num2)

If only one of them is positive

else:

Calculate and print the square of num1 if positive

if num1>=0:

print(num1**2)

Calculate and print the square of num2 if positive

else:

print(num2**2)

3 0

3 years ago

Each TextField has a text property that's returned by its textProperty method as a StringProperty. The StringProperty method ___

masha68 [24]

Answer:

B: Bind

Explanation:

JavaFX property binding permits the synchronization of the value of two properties in such a way that whenever there is a change in one of the properties, there is an immediate update on the value of the other property. In this way, The StringProperty method bind receives an ObservableValue as an argument. When the ObservableValue changes, the bound property is updated accordingly.

4 0

3 years ago

Write a loop that sets each vector element to the sum of itself and the next element, except for the last element which stays th

Gekata [30.6K]

Answer:

Add the following lines of code to the already existing code segment

for (i = 0; i < SCORES_SIZE-1; ++i) {

bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);

}

Explanation:

To do the task in the question, we have to iterate through the vector from the first element i.e. element at index 0 to the second to the last element; i.e. element at last index - 1

We then add each element in this iteration with the next.

This iterates through the vector from 0 to SCORES_SIZE - 1

for (i = 0; i < SCORES_SIZE-1; ++i) {

This adds each vector element with the next

bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);

}

The above should be added before

for (i = 0; i < SCORES_SIZE; ++i) {

cout << bonusScores.at(i) << " ";

}

Also, I've made other modifications to the program.

Proper import of header files
Proper declaration of vector bonusScores

See attachment for complete source code

Download cpp

6 0

3 years ago